/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 89 What is a half-plane?... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is a half-plane?

Short Answer

Expert verified
A half-plane is one of the two regions into which a plane is divided by a line, called a boundary. There are two types of half-planes: open half-plane, where points on the boundary are not included, and closed half-plane, where points on the boundary are included.

Step by step solution

01

Define a Half-Plane

A half-plane is the region of the plane on one side of a line. We could mention that the line, which partitions the plane into two half-planes, is called a boundary line or just boundary.
02

Classify Half-Planes

Half-planes can be classified into two types: open half-plane and closed half-plane. The difference lies on whether the boundary line is included or not in the half-plane. In an open half-plane, points on the line that makes up the boundary are not considered part of the half-plane. In a closed half-plane, the points on the line that makes up the boundary are considered part of the half-plane.
03

Illustrating Examples

It can be helpful to visualize these concepts with a sketch. Imagine drawing a continuous line on a piece of graph paper. The region on one side of that line represents one half-plane, and the region on the other side represents another half-plane.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the domain of each function. Solve: \(\quad \log _{3} x+\log _{3}(x+6)=3\) (Section 4.4,Example 7)

Use the two steps for solving a linear programming problem, given in the box on page \(888,\) to solve the problems. On June \(24,1948,\) the former Soviet Union blocked all land and water routes through East Germany to Berlin. A gigantic airlift was organized using American and British planes to bring food, clothing, and other supplies to the more than 2 million people in West Berlin. The cargo capacity was \(30,000\) cubic feet for an American plane and \(20,000\) cubic feet for a British plane. To break the Soviet blockade, the Western Allies had to maximize cargo capacity but were subject to the following restrictions: \(\cdot\) No more than 44 planes could be used. \(\cdot\) The larger American planes required 16 personnel per flight, double that of the requirement for the British planes. The total number of personnel available could not exceed 512 . \(\cdot\) The cost of an American flight was 9000 and the cost of a British flight was 5000 . Total weekly costs could not exceed $300,000 Find the number of American and British planes that were used to maximize cargo capacity.

Find the domain of each function. \(f(x)=\ln (6-x) \quad \text { (Section } 4.2, \text { Example } 10)\)

When an airplane flies with the wind, it travels 800 miles in 4 hours. Against the wind, it takes 5 hours to cover the same distance. Find the plane’s rate in still air and the rate of the wind.

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I use the coordinates of each vertex from my graph representing the constraints to find the values that maximize or minimize an objective function.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.