/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Solve each system. $$ \left\... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system. $$ \left\\{\begin{aligned} 4 x-y+2 z &=11 \\ x+2 y-z &=-1 \\ 2 x+2 y-3 z &=-1 \end{aligned}\right. $$

Short Answer

Expert verified
The solution to the system is \(x = 1, y = -1, z = 2\).

Step by step solution

01

Eliminate a variable from two pairs of equations

Start by eliminating the variable 'x' from the first and second equation and from the first and third equation. You can do this by multiplying the second equation by 4 and the first by 1, then subtract the second from the first to get a new equation. Similarly, multiply the third equation by 2 and the first by 1, then subtract the third from the first to get another new equation.
02

Solve the system with two variables

Now you have a system of two equations with two variables (y and z). Solve this new system by substitution or elimination. Once done, you should have the values of y and z.
03

Find the value for x

Substitute the found values of y and z back into any of the original three equations and solve for x.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Variable Elimination
Variable elimination is a crucial technique when solving systems of equations. This method focuses on removing one variable to simplify the system. Here's how it works:
- Choose a variable to eliminate. This requires comparing equations and determining which variable is the easiest to remove.
- Use multiplication to adjust coefficients. To successfully eliminate, you may need to multiply one or two equations by numbers that make the coefficients of the chosen variable equal in magnitude but opposite in sign.
- Subtract or add the equations as planned. Doing this removes the chosen variable entirely, resulting in a simpler system. This process can be repeated until the system becomes manageable. The key to variable elimination is careful planning and attentive arithmetic, making sure each step logically progresses to eliminate one unknown at a time.
Substitution Method
In the substitution method, you reformulate one equation so a variable is isolated on one side. It can be particularly effective after using variable elimination. For example:
- Solve one equation for one of the variables. Take one of your simplified equations and express one variable in terms of the others.
- Substitute into another equation. Replace the isolated variable in the remaining equations, simplifying the system further.
- Continue until only one variable is left. Once you have solved for this variable, plug it back into previous equations to find others. This method calls for patience and keen algebraic manipulation. It's useful in both simple and complex systems and strongly ties in with elimination for complete solutions.
Linear Equations
Linear equations form the backbone of a system of equations. These equations have variables raised only to the first power, ensuring they graph as straight lines. Key properties include:
- Consistency. Linear equations may have either one solution, infinitely many solutions, or no solution at all, depending on their alignment or overlap in graph form.
- Simplicity. Each equation can be seen as a line and intersected with others to find common solutions.
Understanding their geometric interpretations helps in visualizing the system's behavior and determining the feasible number of solutions.
Solution of Systems
Solving a system of equations means finding values for the variables that satisfy all equations simultaneously. This process involves:
- Checking for consistency. At the outset, determine if the system has a solution by checking if there is at least one set of values that satisfies all the given equations.
- Applying suitable methods. Use variable elimination or substitution to manage complex systems and arrive at the solutions.
- Verification. Once values are found, put them back into the original equations to confirm correctness. A system might present as two intersecting lines (one solution), the same line (infinite solutions), or parallel lines (no solution). Understanding these potential outcomes is crucial for proper interpretation of results.

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Most popular questions from this chapter

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Exercises \(41-43\) will help you prepare for the material covered in the first section of the next chapter. Solve the system: $$ \left\\{\begin{aligned} w-x+2 y-2 z &=-1 \\ x-\frac{1}{3} y+z &=\frac{8}{3} \\ y-z &=1 \\ z &=3 \end{aligned}\right. $$ Express the solution set in the form {(w, x, y, z)\\} . What makes it fairly easy to find the solution?

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The table shows the price of a gallon of unleaded premium gasoline. For each price, the table lists the number of gallons per day that a gas station sells and the number of gallons per day that can be supplied. $$\begin{array}{lll}{\text { Price per }} & {\text { Gallons Demanded }} & {\text { Gallons Supplied }} \\ {\text { Gallon }} & {\text { per Day }} & {\text { per Day }} \\ {\$ 3.20} & {1400} & {200} \\ {\$ 3.60} & {1200} & {600} \\ {\$ 4.40} & {800} & {1400} \\ {\$ 4.80} & {600} & {1800}\end{array}$$ The data in the table are described by the following demand and supply models: Demand Model \(\quad\) Supply Model \(p=-0.002 x+6 \quad p=0.001 x+3\) a. Solve the system and find the equilibrium quantity and the equilibrium price for a gallon of unleaded premium gasoline. b. Use your answer from part (a) to complete this statement: If unleaded premium gasoline is sold for _____ per gallon, there will be a demand for ______ gallons per day and ______ gallons will be supplied per day.

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