/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 Explain how to solve a nonlinear... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain how to solve a nonlinear system using the addition method. Use \(x^{2}-y^{2}=5\) and \(3 x^{2}-2 y^{2}=19\) to illustrate your explanation.

Short Answer

Expert verified
The solutions for the system of nonlinear equations are \(x = ± \sqrt{5.8}\) and \(y = ± \sqrt{4/5}\)

Step by step solution

01

Write down the equations

First, present both provided equations: \(x^{2}-y^{2}=5\) and \(3 x^{2}-2 y^{2}=19\)
02

Multiply equations to prepare for addition

To be able to eliminate one variable using addition method, both equations should be written in a way that allows the cancellation of one variable. Multiply the first equation by 2, and the second equation by 1, which yields: \(2x^{2}-2y^{2}=10\) and \(3 x^{2}-2 y^{2}=19\)
03

Add the equations

Now, add the two equations to eliminate \(y^{2}\). The result is \(5x^{2} = 29\), or simplified further \(x^{2} = 29/5\)
04

Solve for x

Take the square root on both sides for solving \(x\). Thus, \(x = \sqrt{29/5} = ± \sqrt{5.8}\)
05

Solve for y

Substitute the obtained values of \(x\) into one of the original equations, the first one for instance. You get \(y^{2} = x^{2} - 5 = 5.8 - 5 = 0.8\). Hence, \(y = \sqrt{0.8} = ± \sqrt{4/5}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.