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$$ \left\\{\begin{array}{c} {2 x+y \leq 6} \\ {x+y>2} \\ {1 \leq x \leq 2} \\ {y<3} \end{array}\right. $$

Short Answer

Expert verified
The solution to the system of inequalities is the overlapping region defined by each individual inequality when plotted on the same graph.

Step by step solution

01

Plot first inequality

The inequality \(2x + y \leq 6\) can be rewritten into slope-intercept form by isolating \(y\): \(y \leq -2x + 6\). This indicates a line with a negative slope of -2 and a y-intercept of 6. Since it's inequality 'less than or equal to', the line plot should be solid indicating that points on the line are included in the solution and shading should be below the line.
02

Plot second inequality

The inequality \(x + y > 2\) can be rewritten into slope-intercept form by isolating \(y\): \(y > -x + 2\). This means a line with a negative slope of -1 and a y-intercept of 2. Since it's inequality 'greater than', the line plot should be dashed (indicating that points on the line are not included in the solution) and shading should be above the line.
03

Plot the third inequality

The third inequality \(1 \leq x \leq 2\) indicates that \(x\) ranges between 1 and 2, inclusive. This means a vertical line should be plotted at x=1 and another one at x=2. The shading should be in between these two lines.
04

Plot final inequality

The final inequality \(y < 3\) indicates a horizontal line at \(y = 3\). As it's a strict 'less than' inequality, the line will be dashed and the area below the line should be shaded.
05

Identify the solution region

The solution region where all constraints meet is the overlapping shaded region for all the four inequalities. This area denotes all possible pairs of x and y that satisfy all four inequalities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inequality Graphing
Graphing inequalities is a vital skill in solving systems of inequalities. For instance, when looking at an inequality like \(2x + y \leq 6\), it's important to visualize it. You start by drawing a line represented by \(2x + y = 6\), which acts as the boundary of the inequality. Since this is a 'less than or equal to' scenario, you'll mark the line solid and shade the area below it to represent all the points \(x, y\) that make the inequality true. Inequality graphing is similar to plotting equations, but with the added step of shading to represent the 'greater than' or 'less than' portion of the inequality.

Graphing the second inequality, \(x + y > 2\), follows a similar procedure. Draw a dashed line (because it's not inclusive) for \(x + y = 2\), and shade above this line for the solution set that satisfies the inequality. Overall, graphing each inequality properly helps students visualize and understand the region that satisfies the entire system.
Slope-Intercept Form
Understanding slope-intercept form is crucial when dealing with linear equations and inequalities. It's expressed as \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept of the line. This form is particularly helpful because it allows you to quickly sketch the graph of a line. For example, the inequality \(2x + y \leq 6\) can be rearranged to resemble the slope-intercept form as \(y \leq -2x + 6\). Here \(m = -2\) indicates the slope is downhill, and \(b = 6\) means the line crosses the y-axis at 6. By clearly expressing inequalities in this form, the graphing process becomes a straightforward task of plotting the y-intercept and using the slope to find another point on the line.
Solution Region
The solution region in the context of a system of inequalities is the area where the solutions to all individual inequalities overlap. After graphing each inequality on the same set of axes, the solution region for the system is identified by the area that is shaded for every single inequality. Taking the system from the exercise, after graphing all four inequalities, the solution region is the space that is shaded by all. It's bound by the line \(y = -2x + 6\), with shading below, the line \(y = -x + 2\), with shading above it, and between the vertical lines for \(1 \leq x \leq 2\) and the horizontal line below \(y < 3\). This visual representation is a powerful way to demonstrate the concept of where various conditions can be satisfied simultaneously.

It's important to emphasize that the solution region must satisfy all inequalities at once, meaning each point within the region, when substituted into the inequalities, will make all of them true. The region could be bounded, unbounded, or in some cases, nonexistent if there is no overlap.
Linear Inequalities
Linear inequalities resemble linear equations but instead of an exact line, they define a range of possible solutions. In the given system, we are dealing with linear inequalities like \(2x + y \leq 6\) and \(x + y > 2\). Each inequality has a linear boundary, and the solution set includes the area on one side of this line. The inequality symbols '\(<\)', '\(>\)', '\(\leq\)', and '\(\geq\)' indicate not just the direction of the shading but also whether the boundary line is part of the solution (solid for inclusive inequalities, dashed for exclusive inequalities).

Linear inequalities can restrict variables in various ways, such as limiting 'x' between two values, \(1 \leq x \leq 2\), or restricting 'y' to values less than a certain number, \(y < 3\). When handling multiple linear inequalities, it's the combination of all these restrictions that shapes the solution region we seek to find when solving a system.

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Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Even if a linear system has a solution set involving fractions, such as \(\left\\{\left(\frac{8}{11}, \frac{43}{11}\right)\right\\},\) I can use graphs to determine if the solution set is reasonable.

determine whether each statement makes sense or does not make sense, and explain your reasoning. Use an extension of the Great Question! on page 859 to describe how to set up the partial fraction decomposition of a rational expression that contains powers of a prime cubic factor in the denominator. Give an example of such a decomposition.

a. A student earns \(\$ 15\) per hour for tutoring and \(\$ 10\) per hour as a teacher's aide. Let \(x=\) the number of hours each week spent tutoring and let \(y=\) the number of hours each week spent as a teacher's aide. Write the objective function that models total weekly earnings. b. The student is bound by the following constraints: \(\cdot\) To have enough time for studies, the student can work no more than 20 hours per week. \(\cdot\) The tutoring center requires that each tutor spend at least three hours per week tutoring. \(\cdot\) The tutoring center requires that each tutor spend no more than eight hours per week tutoring. Write a system of three inequalities that models these constraints. c. Graph the system of inequalities in part (b). Use only the first quadrant and its boundary, because \(x\) and \(y\) are nonnegative. d. Evaluate the objective function for total weekly earnings at each of the four vertices of the graphed region. [The vertices should occur at \((3,0),(8,0),(3,17),\) and \((8,12) .]\) e. Complete the missing portions of this statement: The student can earn the maximum amount per week by tutoring for ____ hours per week and working as a teacher's aide for ____ hours per week. The maximum amount that the student can earn each week is $_____.

What is a constraint in a linear programming problem? How is a constraint represented?

$$ \text { Let } f(x)=\left\\{\begin{aligned} x+3 & \text { if } x \geq 5 \\ 8 & \text { if } x<5 \end{aligned}\right. $$

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