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write the form of the partial fraction decomposition of the rational expression. It is not necessary to solve for the constants. $$\frac{5 x^{2}-6 x+7}{(x-1)\left(x^{2}+1\right)}$$

Short Answer

Expert verified
The general form of the partial fraction decomposition of the given rational expression is \(\frac{A}{x-1}+\frac{Bx+C}{x^2+1}\)

Step by step solution

01

Identify the denominator's factors

The given rational expression has a denominator composed of a linear factor \( (x-1) \) and a quadratic factor \( (x^2+1) \)
02

Formulate the general form

As the denominator has one linear and one quadratic factors, the partial fraction decomposition will have the form: \[\frac{A}{x-1}+\frac{Bx+C}{x^2+1}\] where A, B, and C are the constants.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Expression
A rational expression is formed by dividing two polynomials, similar to how a fraction is formed by dividing two numbers. In algebra, when we talk about polynomial fractions, these are referred to as rational expressions. For example, the expression \(\frac{5x^2 - 6x + 7}{(x-1)(x^2 + 1)}\) is a rational expression because both the numerator and the denominator are polynomials.
One common challenge with rational expressions is simplifying or breaking them down into simpler parts, particularly when solving equations or integrating in calculus. This process often involves partial fraction decomposition, which is particularly useful when we have to integrate these expressions or find their limits as x approaches certain values.
In breaking down a rational expression, it is important to identify its components, like the linear or quadratic factors in its denominator, to apply the appropriate methods for decomposition or simplification.
Linear Factor
A linear factor is a polynomial factor of the first degree, meaning that its highest power of the variable (typically x) is one. In the context of rational expressions and partial fraction decomposition, linear factors appear in the denominator and are crucial for determining the form of the decomposition.
For our example \(\frac{5x^2 - 6x + 7}{(x-1)(x^2 + 1)}\), the linear factor from the denominator is \((x-1)\). When we decompose the rational expression into partial fractions, this linear factor gives rise to a term of the form \(\frac{A}{x-1}\), where A is a constant that would be solved for if we were to complete the partial fraction decomposition.
Understanding linear factors allows us to simplify and work with rational expressions more effectively, breaking them into simpler, more manageable pieces for further mathematical operations such as integration or finding solution sets.
Quadratic Factor
A quadratic factor is a second-degree polynomial that can be part of the denominator in a rational expression. Unlike linear factors, quadratic factors have a variable raised to the power of two as their highest degree term, represented in a general form as \(ax^2 + bx + c\).
In our sample rational expression \(\frac{5x^2 - 6x + 7}{(x-1)(x^2 + 1)}\), the quadratic factor is \((x^2 + 1)\). During partial fraction decomposition, this factor leads to a term in the format of \(\frac{Bx + C}{x^2 + 1}\), where B and C are constants. This term is slightly more complex than the one stemming from a linear factor because it incorporates not just a single constant, but a linear expression in the numerator to account for the quadratic term in the denominator.
Quadratic factors are essential for understanding the structure of more complex algebraic expressions and for performing operations such as division, simplification, and integration of algebraic fractions.
Algebraic Fractions
Algebraic fractions are fractions where the numerator, the denominator, or both are algebraic expressions—meaning they include variables, constants, and arithmetic operations (addition, subtraction, multiplication, and sometimes division). The rational expression from our initial example is an algebraic fraction.
In the context of partial fraction decomposition, algebraic fractions are typically decomposed into a sum of simpler fractions to make calculations like integration or solving equations more straightforward. This is especially helpful when dealing with integrals in calculus or simplifying complex expressions in algebra.
By understanding algebraic fractions and how to manipulate them through processes like partial fraction decomposition, students can tackle various mathematical problems with greater ease. It provides a methodical approach for dealing with complex expressions, breaking them down into parts that are simpler to understand and work with.

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Most popular questions from this chapter

Exercises 120–122 will help you prepare for the material covered in the next section. a. Graph the solution set of the system: $$\left\\{\begin{array}{r} {x+y \geq 6} \\ {x \leq 8} \\ {y \geq 5} \end{array}\right.$$ b. List the points that form the corners of the graphed region in part (a). c. Evaluate \(3 x+2 y\) at each of the points obtained in part (b).

An object moves in simple harmonic motion described by \(d=6 \cos \frac{3 \pi}{2} t,\) where \(t\) is measured in seconds and \(d\) in inches. Find: a. the maximum displacement b. the frequency c. the time required for one cycle. (Section \(5.8, \text { Example } 8)\)

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I graphed the solution set of \(y\) as \(x+2\) and \(x \geq 1\) without using test points.

Write a system of equations having {(-2, 7)} as a solution set. (More than one system is possible.)

The table shows the price of a gallon of unleaded premium gasoline. For each price, the table lists the number of gallons per day that a gas station sells and the number of gallons per day that can be supplied. $$\begin{array}{lll}{\text { Price per }} & {\text { Gallons Demanded }} & {\text { Gallons Supplied }} \\ {\text { Gallon }} & {\text { per Day }} & {\text { per Day }} \\ {\$ 3.20} & {1400} & {200} \\ {\$ 3.60} & {1200} & {600} \\ {\$ 4.40} & {800} & {1400} \\ {\$ 4.80} & {600} & {1800}\end{array}$$ The data in the table are described by the following demand and supply models: Demand Model \(\quad\) Supply Model \(p=-0.002 x+6 \quad p=0.001 x+3\) a. Solve the system and find the equilibrium quantity and the equilibrium price for a gallon of unleaded premium gasoline. b. Use your answer from part (a) to complete this statement: If unleaded premium gasoline is sold for _____ per gallon, there will be a demand for ______ gallons per day and ______ gallons will be supplied per day.

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