/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 The sum of two numbers is 7 . If... [FREE SOLUTION] | 91Ó°ÊÓ

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The sum of two numbers is 7 . If one number is subtracted from the other, their difference is \(-1 .\) Find the numbers.

Short Answer

Expert verified
The two numbers are 3 and 4.

Step by step solution

01

Formulate the Equations

From the problem, it can be known that if we let the unknown numbers be \( x \) and \( y \), then we have two equations: \( x + y = 7 \), which represents the sum of the two numbers and \( x - y = -1 \), which represents the difference between the two numbers.
02

Solve the Equations Simultaneously

Since we have two equations, \( x + y = 7 \) and \( x - y = -1 \), we can add these two equations together to eliminate \( y \). So, \( (x + y) + (x - y) = 7 + (-1) \), which simplifies to \( 2x = 6 \). Then, to solve for \( x \), we divide both sides of the equation by 2, giving us \( x = 3 \).
03

Substitute x into Equation

Once we've found \( x = 3 \), we substitute this into the first equation, \( x + y = 7 \). This gives us \( 3 + y = 7 \). To solve for \( y \), we subtract 3 from both sides of the equation, giving \( y = 4 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Systems of Linear Equations
When faced with an algebraic conundrum involving two unknown quantities, one often encounters what is known as a system of linear equations. These are simply equations that map a straight line when plotted on a graph, hence the term 'linear'. The goal is to find a common solution for x and y that satisfies all equations in the system simultaneously.

Consider a scenario where you're given two facts: the sum of two numbers is 7, and their difference is -1. Turning these words into mathematical expressions, you'll end up with two linear equations, which together form a system. Solving such a system often involves methods like substitution, elimination, or graphing to find where these equations intersect—that is, the point where both equations are true—thereby revealing the elusive numbers.
Algebraic Problem-Solving
Algebraic problem-solving can sometimes feel like unravelling a mystery. At its core, it's about understanding and transforming given information into a series of mathematical steps that lead to a solution. It begins by translating the words of a problem into equations that represent the relationship between unknowns. These equations act as critical clues.

Using logical reasoning and algebraic manipulations, such as adding or subtracting entire equations or parts thereof, can unveil the value of unknowns. For the given problem, the journey from knowing the sum and difference of two numbers to discovering the exact numbers themselves exemplifies the essence of algebraic problem-solving. It is a structured approach that navigates through the maze of equations to arrive at the precise values, which in this case, are the two numbers we seek.
Substitution Method
Among the techniques for solving a system of linear equations is the substitution method. This approach is particularly handy when one equation can be solved for an individual variable, which can then be 'substituted' into another equation, simplifying the system one variable at a time.

Take the example where the two numbers add up to 7 and their difference is -1. If you solve the first equation for one number, you can 'substitute' that expression into the second equation, and thereby reduce the system to a single equation with one unknown. From there, solving for the single unknown becomes straightforward. In practice, the substitution method is elegant and powerful, simplifying complex relationships into digestible steps that reveal the underlying values of the unknowns.

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Most popular questions from this chapter

A television manufacturer makes rear-projection and plasma televisions. The profit per unit is 125 for the rear-projection televisions and 200 for the plasma televisions. a. Let \(x=\) the number of rear-projection televisions manufactured in a month and let \(y=\) the number of plasma televisions manufactured in a month. Write the objective function that models the total monthly profit. b. The manufacturer is bound by the following constraints: \(\cdot\) Equipment in the factory allows for making at most 450 rear-projection televisions in one month. \(\cdot\) Equipment in the factory allows for making at most 200 plasma televisions in one month. \(\cdot\) The cost to the manufacturer per unit is 600 for the rear-projection televisions and 900 for the plasma televisions. Total monthly costs cannot exceed 360,000. Write a system of three inequalities that models these constraints. c. Graph the system of inequalities in part (b). Use only the first quadrant and its boundary, because \(x\) and \(y\) must both be nonnegative. d. Evaluate the objective function for total monthly profit at each of the five vertices of the graphed region. [The vertices should occur at \((0,0),(0,200),(300,200)\) \((450,100), \text { and }(450,0) .]\) e. Complete the missing portions of this statement: The television manufacturer will make the greatest profit by manufacturing _____ rear- projection televisions each month and _____ \(-\) plasma televisions each month. The maximum monthly profit is $_____.

Solve each system for \(x\) and \(y,\) expressing either value in terms of a or \(b\), if necessary. Assume that \(a \neq 0\) and \(b \neq 0.\) \(\left\\{\begin{array}{l}{4 a x+b y=3} \\ {6 a x+5 b y=8}\end{array}\right.\)

\(g(x)=\frac{x-6}{x^{2}-36}\) (Section 3.5, Example 1)

When using the addition or substitution method, how can you tell if a system of linear equations has infinitely many solutions? What is the relationship between the graphs of the two equations?

Exercises \(41-43\) will help you prepare for the material covered in the first section of the next chapter. Solve the system: $$ \left\\{\begin{aligned} x+y+2 z &=19 \\ y+2 z &=13 \\ z &=5 \end{aligned}\right. $$

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