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Graph the solution set of each system of inequalities or indicate that the system has no solution. $$ \left\\{\begin{array}{l} {x+y>3} \\ {x+y<-2} \end{array}\right. $$

Short Answer

Expert verified
The system of inequalities has no solution because there is no region in the plane that satisfies both inequalities concurrently.

Step by step solution

01

Graph the first inequality

To graph the inequality \(x + y > 3\), first consider the equal part, i.e., the line \(x + y = 3\). This line divides the plane into two parts. Test a point not on the line (e.g., the origin (0,0)) in the original inequality. The origin doesn't satisfy the inequality, so the solution set for \(x + y > 3\) is the region of the plane on the side of the line opposite to the origin.
02

Graph the second inequality

Similarly, to graph the inequality \(x + y < -2\), first consider the equal part, i.e., the line \(x + y = -2\). This line also divides the plane into two parts. Test a point not on the line (e.g., the origin (0,0)) in the original inequality. The origin satisfies the inequality, so the solution set for \(x + y < -2\) is the region of the plane on the same side of the line as the origin.
03

Identify the intersection

The solution to the system of inequalities is the region where the solution sets to both inequalities overlap. However, in this case, the two regions identified in Step 1 and Step 2 do not intersect. The regions are on opposite sides of the lines corresponding to the inequalities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Inequalities
Understanding how to graph inequalities is the first step toward solving a system of inequalities. Each inequality splits the coordinate plane into two parts. Take, for example, the inequality \(x + y > 3\). This inequality can be initially graphed as the line \(x + y = 3\). This line is crucial because it forms the boundary of the solution region. However, the solution also involves determining which side of the line contains all the points that satisfy the inequality.
To do this, select a test point; a common choice is the origin point \((0,0)\) because it simplifies calculations. Plug in this point to see if it satisfies the inequality. If it doesn’t, then the solution set does not include the side of the line where the origin is located. Hence, for \(x + y > 3\), the solution region is above the line \(x + y = 3\). The line itself generally isn't part of the solution; thus, we use a dashed line to depict this in the graph.

In the same way, graphing \(x + y < -2\) involves first drawing the line \(x + y = -2\). Conduct a similar test using the origin. If it satisfies the inequality, the solution set is on the same side as the origin. For \(x + y < -2\), this means below the line. Again, use a dashed line for the boundary since it is not part of the inequality.
Solution Set
The solution set of a system of inequalities encompasses all the possible points that satisfy all inequalities simultaneously. If you have just one inequality, the solution set is straightforward: it is the region that is on one side of the line you have graphed based on your inequality. Once you have more than one inequality, finding the solution set involves determining where these individual regions overlap after they have been graphed.
For instance, consider our inequalities \(x + y > 3\) and \(x + y < -2\). Each one has its own region of solutions:
  • \(x + y > 3\) has a solution region above its line.
  • \(x + y < -2\) has its solution below its line.
These solution sets are visualized on the graph as shaded regions. The final solution set is ideally where these two shaded regions overlap. This overlap is crucially important as it represents the points satisfying all conditions in our inequality system.
Inequality Intersection
When solving a system of inequalities, finding the intersection of the solution sets is the main goal. This intersection is where all given inequalities share common ground and are simultaneously true. If there is no intersection, the system has no solution, meaning there's no set of values meeting all inequalities.

With our example system \(x + y > 3\) and \(x + y < -2\), visualize the graph. Each inequality region faces away from the other, creating areas that are mutually exclusive:
  • In this case, the above-the-line region for \(x + y > 3\) never reaches the below-the-line region for \(x + y < -2\).
  • Thus, we have no overlap.
This signifies that the system of inequalities lacks a solution region, as their graphically represented solution areas do not intersect. Understanding the non-intersection concept is just as valuable as finding an intersection in a system because it helps confirm no shared solutions exist.

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Most popular questions from this chapter

Expand: \(\log _{8}\left(\frac{\sqrt[4]{x}}{64 y^{3}}\right) .\) (Section 4.3, Example 4)

Explain how to solve a system of equations using the addition method. Use \(3 x+5 y=-2\) and \(2 x+3 y=0\) to illustrate your explanation.

A television manufacturer makes rear-projection and plasma televisions. The profit per unit is 125 for the rear-projection televisions and 200 for the plasma televisions. a. Let \(x=\) the number of rear-projection televisions manufactured in a month and let \(y=\) the number of plasma televisions manufactured in a month. Write the objective function that models the total monthly profit. b. The manufacturer is bound by the following constraints: \(\cdot\) Equipment in the factory allows for making at most 450 rear-projection televisions in one month. \(\cdot\) Equipment in the factory allows for making at most 200 plasma televisions in one month. \(\cdot\) The cost to the manufacturer per unit is 600 for the rear-projection televisions and 900 for the plasma televisions. Total monthly costs cannot exceed 360,000. Write a system of three inequalities that models these constraints. c. Graph the system of inequalities in part (b). Use only the first quadrant and its boundary, because \(x\) and \(y\) must both be nonnegative. d. Evaluate the objective function for total monthly profit at each of the five vertices of the graphed region. [The vertices should occur at \((0,0),(0,200),(300,200)\) \((450,100), \text { and }(450,0) .]\) e. Complete the missing portions of this statement: The television manufacturer will make the greatest profit by manufacturing _____ rear- projection televisions each month and _____ \(-\) plasma televisions each month. The maximum monthly profit is $_____.

An objective function and a system of linear inequalities representing constraints are given. a. Graph the system of inequalities representing the constraints. b. Find the value of the objective function at each corner of the graphed region. c. Use the values in part (b) to determine the maximum value of the objective function and the values of \(x\) and \(y\) for which the maximum occurs. Objective Function Constraints $$ \begin{aligned} &z=2 x+4 y\\\ &\left\\{\begin{array}{l} {x \geq 0, y \geq 0} \\ {x+3 y \geq 6} \\ {x+y \geq 3} \\ {x+y \leq 9} \end{array}\right. \end{aligned} $$

Consider the objective function \(z=A x+B y(A>0\) and \(B>0\) ) subject to the following constraints: \(2 x+3 y \leq 9\) \(x-y \leq 2, x \geq 0,\) and \(y \geq 0 .\) Prove that the objective function will have the same maximum value at the vertices \((3,1)\) and \((0,3)\) if \(A=\frac{2}{3} B\).

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