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write the partial fraction decomposition of each rational expression. $$\frac{x^{2}+2 x+3}{\left(x^{2}+4\right)^{2}}$$

Short Answer

Expert verified
The partial fraction decomposition would be in the form \(f(x) = \frac{Ax+B}{x^{2} + 4} + \frac{Cx+D}{(x^{2} + 4)^{2}}\), where A, B, C, and D are constants determined from equating the original rational function to the general form and solving for these constants.

Step by step solution

01

Factor the Denominator

The denominator in this problem is \((x^{2} + 4)^{2}\). This is a square of a binomial. Factoring won't break this base any further, therefore, we can consider \((x^{2} + 4)\) as an irreducible factor.
02

Write general form of fractions

For each irreducible quadratic factor of the denominator, we will have a corresponding term in the form of \(\frac{Ax+B}{(x^{2} + 4)}\) in the partial fractions decomposition, where A and B are constants. However, since this factor is being squared in the denominator, then there will be two such terms in the decomposition. This gives us the general form \(\frac{Ax+B}{x^{2} + 4} + \frac{Cx+D}{(x^{2} + 4)^{2}}\).
03

Solve for constants

Set the original rational function \((x^{2}+2 x+3)/(x^{2}+4)^{2}\) equal to the general form from step 2 and solve for the constants A, B, C, and D. Simplify and compare the coefficients on both sides for each power of x. The system of equations obtained from comparing the coefficients can then be solved to obtain the values of A, B, C, and D.
04

Write the partial fraction decomposition

Use the values of A, B, C, and D obtained from step 3 to write the partial fraction decomposition of the original rational function. The function will be in the form \(f(x) = \frac{Ax+B}{x^{2} + 4} + \frac{Cx+D}{(x^{2} + 4)^{2}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Expressions
Rational expressions, such as \(\frac{x^2+2x+3}{(x^2+4)^2}\), represent ratios of two polynomials where the numerator and the denominator can be any polynomial. Understanding rational expressions is key to mastering algebra, as they appear in various topics such as simplification, solving equations, and calculus. In the context of partial fraction decomposition, the goal is to break down complex rational expressions into simpler fractions that are easier to work with, especially for integration or finding limits.

When dealing with rational expressions, the first step is usually to factor the polynomials if possible. This initial step greatly aids in simplifying the expression, identifying restrictions, and setting the stage for further operations such as decomposition. It's vital to understand that the denominator of a rational expression cannot be zero, as division by zero is undefined, so we must also keep track of the values that make the denominator zero to avoid them in our calculations.
Factoring Polynomials
Factoring polynomials is the process of breaking down a complicated polynomial into products of simpler ones. For instance, the polynomial \(x^2 - 9\) can be factored into \(x + 3)(x - 3)\). However, not all polynomials are factored so easily. Some remain 'irreducible', which means they cannot be factored over the rationals.

Polynomials play an essential role in the decomposition of rational expressions since the denominator's factors determine the structure of the partial fraction decomposition. To illustrate, for a denominator like \(\left(x^2 + 4\right)^2\), one would attempt to factor it, but as it is already irreducible, it serves as a basis for setting up our partial fractions.
Irreducible Quadratic Factors
An irreducible quadratic factor refers to a quadratic polynomial that cannot be factored further over the set of real numbers. For example, \(x^2 + 4\) is irreducible because it has no real roots. These irreducible factors are significant in partial fractions decomposition as they give rise to terms in the decomposed form that include both linear and constant terms in the numerator.

When dealing with an irreducible quadratic factor that is raised to a power, as in \(\left(x^2 + 4\right)^2\), it generates multiple terms in the decomposition. Each power of the irreducible factor leads to an additional term in the partial fractions. Thus, in our decomposition, we will have terms with \(x^2 + 4\) in the denominator and another with \(\left(x^2 + 4\right)^2\), each with their own unique constants in the numerators.
System of Equations
After establishing the general form of the partial fraction decomposition, the next challenge is solving for the unknown constants. This task involves creating a system of equations by equating coefficients of like terms on both sides of an equation. For the expression \(\frac{x^2+2x+3}{(x^2+4)^2}\), we set it equal to the partial fraction form and match coefficients for each power of \(x\).

This gives us a set of equations that can be solved using methods like substitution, elimination, or matrix operations. Solving this system provides us with the constants for the partial fraction decomposition. In our case, we aim to find the values of \(A\), \(B\), \(C\), and \(D\) that will correctly represent the original rational expression as a sum of simpler fractions.

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Most popular questions from this chapter

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When is it easier to use the addition method rather than the substitution method to solve a system of equations?

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