/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Solve each system by the additio... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each system by the addition method. \(\left\\{\begin{array}{l}{x+y=6} \\ {x-y=-2}\end{array}\right.\)

Short Answer

Expert verified
The solutions for the system of equations are (1,0) and (-1,0).

Step by step solution

01

Add the two equations

First, both equations need to be added together. As a result, we get: \(4x^{2} - y^{2} + 4x^{2} + y^{2} = 4 + 4\). This simplifies to \(8x^{2} = 8\).
02

Solve for the remaining variable

To solve for \(x\), divide each side of the simplified equation by 8. The final equation becomes \(x^{2} = 1\). Take the square root of both sides, we get \(x = ±1\).
03

Substitute x into original equations

Substitute \(x = 1\) into the first original equation, we get: \(4(1)^{2} - y^{2} = 4\), which simplifies to \(4 - y^{2} = 4\). Therefore, \(y = 0\). We do the same for \(x = -1\) and get the same result.
04

Give the solutions

Given the results from the steps above, the solutions for the system of equations are (1,0) and (-1,0).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Systems
Dealing with quadratic systems involves finding the set of values that satisfy multiple equations simultaneously. In the given exercise, we encounter a system comprising two equations with squares of the variables, indicating a quadratic nature. The key to solving such quadratic systems lies in manipulating the equations to isolate variables and eliminate terms.

To grasp the essence of solving quadratic systems, remember that these systems can have more than one solution, reflecting the multiple intersection points between a parabola and a line, circle, or another parabola. In the provided example, the addition method effectively combines the two equations to reduce the system to a simpler form where the variable can be solved.
Algebraic Methods
Algebraic methods encompass a variety of techniques to solve equations and systems of equations, including the addition, substitution, and elimination methods. These methods are the foundational tools used in algebra to manipulate and solve equations. For instance, the addition method employed in our example facilitates the elimination of one variable by adding two equations, which eventually simplifies the system to a solvable state.

Algebraic methods can be particularly powerful as they are based on logical steps that maintain the equality of the equations. The outcomes of these methods provide the solutions that are the points of intersection in a Cartesian plane, illustrating the real-world significance of these abstract calculations.
Systems of Nonlinear Equations
Systems consisting of at least one equation that is not linear are known as systems of nonlinear equations. These systems can consist of quadratic equations, cubic equations, or any higher order, as well as transcendental equations involving sine, cosine, exponential functions, etc. Solving such systems requires more advanced algebraic methods as the simple linear superposition principle does not apply.

Our textbook example features a system of quadratic equations, which is a common case of nonlinear systems. When solving such systems, the goal is to reduce them to linear ones if possible, or propose a strategic approach—like the addition method—to simplify and solve them. The complex nature of nonlinear systems often results in multiple solutions or no solution at all, underscoring the importance of methodical problem-solving.
Substitution Method
The substitution method is another algebraic technique that solves systems of equations by expressing one variable in terms of another and substituting this expression into the other equation. This method can sometimes simplify the process of finding the solution, especially when one equation in the system is easier to manipulate.

While our textbook example uses the addition method, the substitution method could also be employed if one equation could be rearranged to solve for a single variable. Substitution could then reduce the system to a single equation in one variable. It is an excellent alternative method when the equations are not as conveniently arranged for addition or elimination. Understanding when and how to apply the substitution method is a valuable skill in a mathematician's toolkit and is often used alongside other methods for more complex systems.

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Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I graphed the solution set of \(y\) as \(x+2\) and \(x \geq 1\) without using test points.

Members of the group should interview a business executive who is in charge of deciding the product mix for a business. How are production policy decisions made? Are other methods used in conjunction with linear programming? What are these methods? What sort of academic background, particularly in mathematics, does this executive have? Present a group report addressing these questions, emphasizing the role of linear programming for the business.

Perform the operations and write the result in standard form: $$\frac{-20+\sqrt{-32}}{10}$$

Use the two steps for solving a linear programming problem, given in the box on page \(888,\) to solve the problems. You are about to take a test that contains computation problems worth 6 points each and word problems worth 10 points each. You can do a computation problem in 2 minutes and a word problem in 4 minutes. You have 40 minutes to take the test and may answer no more than 12 problems. Assuming you answer all the problems attempted correctly, how many of each type of problem must you answer to maximize your score? What is the maximum score?

Will help you prepare for the material covered in the next section. a. Graph the solution set of the system: \(\left\\{\begin{aligned} x & \geq 0 \\ y & \geq 0 \\ 3 x-2 y & \leq 6 \\ y & \leq-x+7 \end{aligned}\right.\) b. List the points that form the corners of the graphed region in part (a). c. Evaluate \(2 x+5 y\) at each of the points obtained in part (b).

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