/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 In converting \(r=\sin \theta\) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In converting \(r=\sin \theta\) from a polar equation to a rectangular equation, describe what should be done to both sides of the equation and why this should be done.

Short Answer

Expert verified
To convert the polar equation \(r = \sin \theta\) into a rectangular equation, we substitute \(r\) by \(y / \sin \theta\) from the conversion formula, resulting in the rectangular equation \(y = \sin^2 \theta\).

Step by step solution

01

Understand Conversion Formulas

The first step is to understand the conversion formulas between polar and rectangular coordinates. We have the equations \(x = r \cos \theta\) and \(y = r \sin \theta\). Inverting the second equation yields \(r = y / \sin \theta\).
02

Substitute Polar Equation

In the next step, replace \(r\) in the polar equation \(r = \sin \theta\) by \(y / \sin \theta\), obtained from the conversion formula. This gives the equation \(y / \sin \theta = \sin \theta\).
03

Simplify Equation

Now, simplify this equation by multiplying both sides by \(\sin \theta\) to remove the denominator on the left side. This yields the rectangular equation \(y = \sin^2 \theta\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.