Chapter 5: Problem 99
Explain why, without restrictions, no trigonometric function has an inverse function.
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Chapter 5: Problem 99
Explain why, without restrictions, no trigonometric function has an inverse function.
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Determine the domain and the range of each function. $$ f(x)=\sin \left(\sin ^{-1} x\right) $$
How do we measure the distance between two points, \(A\) and \(B,\) on Earth? We measure along a circle with a center, \(C,\) at the center of Earth. The radius of the circle is equal to the distance from \(\mathrm{C}\) to the surface. Use the fact that Earth is a sphere of radius equal to approximately 4000 miles to solve Exercises 93-96. If \(\theta=10^{\circ},\) find the distance between \(A\) and \(B\) to the nearest mile.
Determine the domain and the range of each function. $$ f(x)=\sin ^{-1} x+\cos ^{-1} x $$
For years, mathematicians were challenged by the following problem: What is the area of a region under a curve between two values of \(x ?\) The problem was solved in the seventeenth century with the development of integral calculus. Using calculus, the area of the region under \(y=\frac{1}{x^{2}+1},\) above the \(x\) -axis, and between \(x=a\) and \(x=b\) is \(\tan ^{-1} b-\tan ^{-1} a\). Use this result, shown in the figure, to find the area of the region under \(y=\frac{1}{x^{2}+1}\) above the \(x\) -axis, and between the values of a and b given in Exercises \(97-98\). (GRAPH CANNOT COPY) \(a=-2\) and \(b=1\)
Prove that if \(x>0, \tan ^{-1} x+\tan ^{-1} \frac{1}{x}=\frac{\pi}{2}\).
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