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Determine the amplitude and period of each function. Then graph one period of the function. $$y=\sin 2 x$$

Short Answer

Expert verified
The amplitude of the function \(y=\sin 2 x\) is 1 and the period is \(\pi\).

Step by step solution

01

Determine Amplitude

The amplitude is the absolute value of the coefficient of the sine function. In this case, the coefficient is 1. So the amplitude of the function \(y=\sin 2 x\) is \(1\).
02

Determine Period

The period of the sine function is calculated by the formula \(\text{Period} = \frac{2\pi}{|B|}\), where B is the coefficient of x in the function. In this case, B is 2. So the period of the function \(y=\sin 2 x\) is \(\frac{2\pi}{2} = \pi\).
03

Sketching the Graph

The graph of \(y=\sin 2 x\) starts at the origin (0,0), reaches its peak at the amplitude (which is 1 in this case) at \(x=\frac{\pi}{4}\), returns back to 0 at \(x=\frac{\pi}{2}\), minimises at \(x=\frac{3\pi}{4}\), and completes one period at \(x = \pi\). This behaviour continues for other values of x, spanned across \(-\infty\) to \(+\infty\). Thus, the wave is compressed horizontally, with a peak and trough occurring more frequently than the standard sine function.

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