Chapter 5: Problem 27
In Exercises \(21-28,\) convert each angle in radians to degrees. $$ -3 \pi $$
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Chapter 5: Problem 27
In Exercises \(21-28,\) convert each angle in radians to degrees. $$ -3 \pi $$
These are the key concepts you need to understand to accurately answer the question.
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Determine whether each statement makes sense or does not make sense, and explain your reasoning. Because \(y=\sin x\) has an inverse function if \(x\) is restricted to \(\left[-\frac{\pi}{2}, \frac{\pi}{2}\right],\) they should make restrictions easier to remember by also using \(\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\) as the restriction for \(y=\tan x\).
The angular speed of a point on Earth is \(\frac{\pi}{12}\) radian per hour. The Equator lies on a circle of radius approximately 4000 miles. Find the linear velocity, in miles per hour, of \(\overline{\mathbf{a}}\) point on the Equator.
We will prove the following identities: $$\begin{array}{l} {\sin ^{2} x=\frac{1}{2}-\frac{1}{2} \cos 2 x} \\ {\cos ^{2} x=\frac{1}{2}+\frac{1}{2} \cos 2 x} \end{array}$$ Use the identity for \(\cos ^{2} x\) to graph one period of \(y=\cos ^{2} x\)
For years, mathematicians were challenged by the following problem: What is the area of a region under a curve between two values of \(x ?\) The problem was solved in the seventeenth century with the development of integral calculus. Using calculus, the area of the region under \(y=\frac{1}{x^{2}+1},\) above the \(x\) -axis, and between \(x=a\) and \(x=b\) is \(\tan ^{-1} b-\tan ^{-1} a\). Use this result, shown in the figure, to find the area of the region under \(y=\frac{1}{x^{2}+1}\) above the \(x\) -axis, and between the values of a and b given in Exercises \(97-98\). (GRAPH CANNOT COPY) \(a=-2\) and \(b=1\)
Use a right triangle to write each expression as an algebraic expression. Assume that \(x\) is positive and that the given inverse trigonometric function is defined for the expression in \(x\). $$ \sin \left(\tan ^{-1} x\right) $$
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