/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 Use properties of logarithms to ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use properties of logarithms to condense each logarithmic expression. Write the expression as a single logarithm whose coefficient is \(1 .\) Where possible, evaluate logarithmic expressions without using a calculator. $$ 2 \ln x-\frac{1}{2} \ln y $$

Short Answer

Expert verified
The given expression \(2 \ln x-\frac{1}{2} \ln y\) can be condensed to a single logarithm as \( \ln \left( \frac{x^2}{y^{1/2}} \right) \).

Step by step solution

01

Apply the power rule

The first step is to apply the power rule. The power rule states that the coefficient of a logarithm can become the exponent of the argument. So, the given expression, \(2 \ln x - \frac{1}{2} \ln y\), using the power rule, becomes \( \ln x^2 - \ln y^{1/2} \).
02

Apply the properties of logarithms for subtraction

Next, we see a difference (or subtraction) between two logarithms - the property for this states that the difference of two logs equates to the log of the quotient of their arguments. So, we can write the expression:\( \ln x^2 - \ln y^{1/2} \) as \( \ln \left( \frac{x^2}{y^{1/2}} \right) \).
03

Simplify the expression

The last step is to simplify the expression. In this case, as no numerical values are provided for x and y, and there is no further simplification available, \( \ln \left( \frac{x^2}{y^{1/2}} \right) \) would be our final expression.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Condensation
Understanding logarithm condensation is critical when it comes to simplifying complex logarithmic expressions and making sense of exponential relationships. The process of 'condensing' involves taking multiple logarithmic terms and combining them into a single term. This is particularly helpful when working with equations that require a single logarithmic term.

The power of logarithm condensation is best seen when subtracting or adding logarithmic expressions with the same base. According to the properties of logarithms, you can combine these expressions by converting the addition into multiplication and subtraction into division within the argument of the logarithm.

For instance, in our example, the expression starts with two separate logs, which we can convert into a single term by subtracting their arguments—the result of which is notated as the logarithm of a quotient. This method streamlines the expression and sets the stage for any further algebraic manipulation or for solving the given variables.
Power Rule Logarithms
When it comes to power rule logarithms, mastery of this rule can dramatically simplify the evaluation of logarithmic expressions. The power rule for logarithms allows you to take the exponent of a logarithm’s argument and express it as a multiple of the logarithm itself. This helps in breaking down complex logarithmic terms into simpler components.

In the problem provided, we applied the power rule by transforming the coefficient of the logarithm into the exponent of its argument. For example, the coefficient '2' in front of the \(\ln x\) became the exponent of 'x', effectively rewriting \(2 \ln x\) as \(\ln x^2\). Similarly, the coefficient \(\frac{1}{2}\) was used to adjust the exponent on 'y', turning \(\frac{1}{2} \ln y\) into \(\ln y^{1/2}\). This is an indispensable technique for condensing logarithmic expressions and should be well understood for deeper engagement with logarithms.
Logarithmic Expressions
Dealing with logarithmic expressions is a common challenge in mathematics, but understanding their properties can unlock the ability to simplify and evaluate them with ease. Logarithmic expressions relate to how many times we must multiply a base number to achieve another number. The properties governing these expressions include the product rule, quotient rule, and power rule, among others.

These properties allow us to navigate between logarithmic and exponential forms, to condense multiple logs into a single one, or to expand a single log into multiple terms—providing flexibility in mathematical problem solving. When you encounter a logarithmic expression, identify if any of these properties can apply to condense, expand, or manipulate it for the task at hand. In the step-by-step solution shown here, you can see how applying these properties allows for the combining and simplification of multiple logs into a coherent, simplified form.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Because I cannot simplify the expression \(b^{m}+b^{n}\) by adding exponents, there is no property for the logarithm of a sum.

Explaining the Concepts How can you tell whether an exponential model describes exponential growth or exponential decay?

This group exercise involves exploring the way we grow. - Group members should create a graph for the function that models the percentage of adult height attained by a boy who is \(x\) years old, \(f(x)=29+48.8 \log (x+1) .\) Let \(x=5,6\) \(7, \ldots ., 15,\) find function values, and connect the resulting points with a smooth curve. Then create a graph for the function that models the percentage of adult height attained by a girl who is \(x\) years old, \(g(x)=62+35 \log (x-4)\) Let \(x=5,6,7, \ldots, 15,\) find function values, and connect the resulting points with a smooth curve. Group members should then discuss similarities and differences in the growth patterns for boys and girls based on the graphs.

In Example I on page \(520,\) we used two data points and an exponential function to model the population of the United States from 1970 through 2010 . The data are shown again in the table. Use all five data points to solve Exercises \(66-70\). $$ \begin{array}{cc} {x, \text { Number of Years }} & {y, \text { U.S. Population }} \\ {\text { after } 1969} & {\text { (millions) }} \\ {1(1970)} & {203.3} \\ {11(1980)} & {226.5} \\ {21(1990)} & {248.7} \\ {31(2000)} & {281.4} \\ {41(2010)} & {308.7} \end{array} $$ a. Use your graphing utility's exponential regression option to obtain a model of the form \(y=a b^{x}\) that fits the data. How well does the correlation coefficient, \(r,\) indicate that the model fits the data? b. Rewrite the model in terms of base \(e .\) By what percentage is the population of the United States increasing each year?

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Because the equations $$\log (3 x+1)=5 \text { and } \log (3 x+1)=\log 5$$ are similar, I solved them using the same method.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.