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In Exercises 21–42, evaluate each expression without using a calculator. $$ \log _{5} \frac{1}{5} $$

Short Answer

Expert verified
-1

Step by step solution

01

Analyze the Exponent

Recognize that 5 and 1/5 are related with an exponent of -1 as \(5^{-1} = 1/5\). The exponent -1 signifies an inverse of the base (5), which is 1/5 in this case.
02

Apply Logarithm Rule

Remember the property of logarithm: \(\log_b b^y =y\). When the base of the logarithm and the base of the number to which the logarithm is applied are the same, the result is simply the exponent. The property directly gives the answer when the logarithm is of the form \(\log_b b^y\). Here, base is 5 and the number is 1/5, which is equal to \(5^{-1}\).
03

Evaluate the Logarithm

Put base 5 and exponent -1 into the log form \(\log_b b^y =y\). Here \(b= 5\), \(y=-1\). So, \(\log_5 5^{-1} =-1\). This means the logarithm base 5 of 1/5 is equal to -1. That's the solution without need of a calculator.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Functions
Logarithmic functions are the inverse of exponential functions, and they play a crucial role in various fields, including mathematics and engineering. Understanding these functions requires familiarization with logarithms, which represent the power to which a base number must be raised to obtain a certain value. For instance, the logarithm of a number to a given base is the exponent by which the base must be raised to produce that number.

When you see an expression like \( \log_{5} \frac{1}{5} \), you're looking at a logarithm (log) with base 5. The argument of the logarithm here is \( \frac{1}{5} \). The goal is to figure out what power 5 must be raised to, to get \( \frac{1}{5} \). In simpler terms, the logarithm answers the question: 'To what exponent should 5 be raised to get \( \frac{1}{5} \)?' With this in mind, we can see that logarithmic functions are useful for finding unknown exponents, especially when dealing with equations where the exponents are variables.
Exponent Rules
Exponent rules, also known as the laws of exponents, are a set of guidelines that clarify how to handle calculations involving exponents. These rules are key to simplifying expressions and solving equations that include powers and roots. Several important exponent rules include the product rule (\( a^m \cdot a^n = a^{m+n} \)), the quotient rule (\( \frac{a^m}{a^n} = a^{m-n} \)), and the power rule (\( (a^m)^n = a^{mn} \)).

Understanding these rules is fundamental for working with logarithmic functions since the properties of logarithms closely follow the exponent rules. For example, \( \log_{b}(a \cdot c) \), can be separated into \( \log_{b}(a) + \log_{b}(c) \) due to the product rule for exponents. Applying exponent rules helps to recognize that expressions like \( \frac{1}{5} \) can be written as \( 5^{-1} \) indicating an inverse relationship between the base 5 and its exponent -1, which simplifies the process of evaluating logarithmic expressions without a calculator.
Inverse Operations
Inverse operations are mathematical operations that reverse the effect of another operation. For example, addition and subtraction are inverses of each other, as are multiplication and division. Similarly, exponential functions and logarithmic functions are inverses.

Consider an exponential equation \( b^y = x \). The inverse operation to solve for y is the logarithm: \( \log_{b}(x) = y \). This inverse property explains why logarithms are so useful in algebra, because they allow us to 'undo' the exponentiation process. In practice, when we evaluate \( \log_{5} \frac{1}{5} \) as in the given exercise, we apply this concept of inverse operations. Knowing that 5 raised to the power of -1 is \( \frac{1}{5} \) allows us to directly apply the logarithm's property that links it to exponentiation, simplifying complexity and providing an easier path to finding the solution without resorting to calculators.

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