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Use the exponential decay model for carbon-14, \(A=A_{0} e^{-0.000121 t}\) to solve Exercises \(19-20\) Skeletons were found at a construction site in San Francisco in \(1989 .\) The skeletons contained \(88 \%\) of the expected amount of carbon- 14 found in a living person. In \(1989,\) how old were the skeletons?

Short Answer

Expert verified
The skeletons found in 1989 are approximately \(t\) years old.

Step by step solution

01

Identify given values

In this scenario, it was identified that the skeletons found in 1989 contained 88 percent of the expected amount of carbon-14 found in a living person. So, the remaining amount of carbon-14 which is \(A = 0.88A_0\). The time \(t\) is what we are trying to find.
02

Substitute the values into the decay model

Substitute the given values into the decay model, we get \(0.88A_0 = A_0e^{-0.000121t}\).
03

Simplify the equation

Divide both sides of the equation by \(A_0\), we get \(0.88 = e^{-0.000121t}\).
04

Solve for \(t\)

Taking the natural logarithm of both sides will allow us to remove the exponential, \(ln(0.88) = -0.000121t\). Rearrange the equation to solve for \(t\), \(t = \frac{ln(0.88)}{-0.000121}\).
05

Calculate the age

By calculating the equation, find the approximate value for \(t\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbon-14 Dating
Carbon-14 dating, also known as radiocarbon dating, is a method used by archaeologists and historians to determine the age of organic materials. The principle behind this technique is fairly simple: while a plant or animal is alive, it continuously exchanges carbon with its surroundings, maintaining a consistent level of carbon-14, a radioactive isotope. Once it dies, the exchange stops, and the carbon-14 begins to decay at a predictable rate, known as its half-life.

The model for exponential decay of carbon-14 is represented by the equation \(A=A_{0} e^{-0.000121 t}\), where \(A\) is the remaining amount of carbon-14, \(A_{0}\) is the original amount when the organism died, and \(t\) is the time that has passed in years. To determine the age of the skeletons found in San Francisco, we see that they had 88% of the carbon-14 they would have had when alive. This percentage allows us to estimate how long ago the organism stopped exchanging carbon with the environment, thereby providing us an estimate of the age of the samples.
Natural Logarithm
The natural logarithm, denoted as \(ln\), is the logarithm to the base \(e\), where \(e\) is an irrational and transcendental number approximately equal to 2.71828. This constant arises naturally in mathematics when dealing with continuous growth or decay processes.

In our carbon-14 dating problem, the natural logarithm is used to isolate the time variable, \(t\), from the exponential decay equation. To remove the base \(e\) from the exponent and solve for \(t\), we take the natural logarithm of both sides, resulting in the equation \(ln(0.88) = -0.000121t\). From here, we can easily solve for \(t\) by dividing both sides of the equation by the decay constant, \(-0.000121\text{ year}^{-1}\), giving us the age of the skeletons.
Radioactive Decay
Radioactive decay is a statistical process by which an unstable atomic nucleus loses energy by releasing radiation. In the context of carbon-14 dating, we deal with the decay of the carbon-14 isotope. It has a predictable decay rate, which is expressed as a half-life – the time required for half of the isotope to decay. This half-life is not affected by factors such as temperature, pressure, or chemical environment, making it an excellent clock for dating.

The process of decay for carbon-14 is an exponential one, hence why the decay model is an exponential equation. As an isotope decays, it converts into a different element or isotope at a rate proportional to its current value. This relationship between the remaining amount of the isotope and time is what allows scientists to date ancient organic materials using the proportion of carbon-14 that remains in a sample.

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Most popular questions from this chapter

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