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Use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. $$ \ln \left(\frac{e^{2}}{5}\right) $$

Short Answer

Expert verified
The simplified form of the given logarithmic expression \( \ln(e^2/5) \) is \( 2 - \ln(5) \).

Step by step solution

01

Use the Quotient Rule for Logarithms

The Quotient Rule of Logarithms, states that \( \ln(a/b) = \ln(a) - \ln(b) \). If we apply this rule to the given expression, we would get: \( \ln(e^2)/5 = \ln(e^2) - \ln(5) \)
02

Use the Power Rule for Logarithms

The Power Rule of Logarithms says that \( \ln(a^b) = b * \ln(a) \). Apply this for \( \ln(e^2) \): that means \( \ln(e^2) = 2 * \ln(e) \). So the expression from Step 1 now looks as follows: \( 2 * \ln(e) - \ln(5) \)
03

Evaluating the Logarithmic Expression

The base of a natural logarithm is \(e\), therefore \( \ln(e) = 1 \). That means the expression from Step 2 becomes: \( 2 * 1 - \ln(5) \)
04

Simplify the Expression

After carrying out the remaining arithmetic, the expression simplifies to: \( 2 - \ln(5) \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule for Logarithms
Logarithms have certain properties that simplify their manipulation and calculation, and one such property is the Quotient Rule for Logarithms. This rule is immensely helpful when you're dealing with the logarithm of a division between two expressions.

Specifically, the Quotient Rule states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator, formally written as \( \log_b\left(\frac{a}{b}\right) = \log_b(a) - \log_b(b) \). This applies to all logarithms, including natural logarithms (\ln) which have a base of \(e\), the Euler's number.

By applying this rule, complex expressions can be broken down into simpler parts, making them easier to handle and, if possible, to evaluate without a calculator. It's a fundamental step that lays the groundwork for further simplification and evaluation of logarithmic expressions.
Power Rule for Logarithms
When it comes to powers within logarithms, the Power Rule for Logarithms comes into play. This rule is crucial for unraveling expressions where the argument of the logarithm is raised to a power.

The Power Rule states that the logarithm of a power is equal to the exponent times the logarithm of the base, mathematically represented as \( \log_b(a^c) = c \cdot \log_b(a) \). In practice, this allows you to pull out exponents to the front, turning a potentially complex calculation into a simpler multiplication problem.

This property not only simplifies the expression but also can reveal opportunities to evaluate logarithmic terms, especially when the base of the logarithm and the base of the exponent align, as they often do with natural logarithms. By mastering the Power Rule, students can confidently tackle a wide range of logarithmic expressions, transforming them into a more digestible format.
Evaluating Logarithmic Expressions
Evaluating logarithmic expressions involves finding the numerical value of the expression, which is sometimes possible to do without the use of a calculator. This aspect of logarithms extends from understanding their properties and the relationships between numbers and their logarithms.

For instance, one key relationship is that the logarithm of any number to its own base is 1, such as \( \log_b(b) = 1 \). This is particularly true for natural logarithms, where \( \ln(e) = 1 \) because the base of natural logarithms is \(e\).

Knowing these relationships allows you to simplify expressions that may seem complex at first glance. Being skilled in evaluating logarithms means being able to recognize when a logarithm can be calculated directly and integrating this step into the process of simplifying the overall expression.
Simplifying Logarithmic Expressions
Simplifying logarithmic expressions is all about making them as basic and straightforward as possible. It's an essential skill that combines the use of properties like the Quotient Rule and the Power Rule, along with an understanding of how to evaluate specific logarithmic values.

Through simplification, not only is the appearance of the expression made cleaner, but you also set it up for further operations, be it solving equations, graphing, or applying calculus-related processes. The goal is to express the logarithm in the simplest form, transforming it into manageable terms or even into a single number whenever possible.

Students must pay careful attention to each step of the process, ensuring that they apply the logarithmic rules correctly and evaluate expressions wherever they can. The exercise of expanding, simplifying, and evaluating logarithmic expressions is a beautiful orchestration of algebra skills that deepens your understanding of the logarithmic functions' behavior and properties.

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Most popular questions from this chapter

The exponential growth models describe the population of the indicated country, \(A,\) in millions, t years after 2006 . $$ \begin{array}{ll} {\text { Canada }} & {A=33.1 e^{0.009 t}} \\ {\text { Uganda }} & {A=28.2 e^{0.034 t}} \end{array} $$ Use this information to determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. By \(2009,\) the models indicate that Canada's population will exceed Uganda's by approximately 2.8 million.

a. Use a graphing utility (and the change-of-base property) to graph \(y=\log _{3} x\) b. Graph \(y=2+\log _{3} x, y=\log _{3}(x+2),\) and \(y=-\log _{3} x\) in the same viewing rectangle as \(y=\log _{3} x .\) Then describe the change or changes that need to be made to the graph of \(y=\log _{3} x\) to obtain each of these three graphs.

Explaining the Concepts Nigeria has a growth rate of 0.025 or \(2.5 \% .\) Describe what this means.

In Example I on page \(520,\) we used two data points and an exponential function to model the population of the United States from 1970 through 2010 . The data are shown again in the table. Use all five data points to solve Exercises \(66-70\). $$ \begin{array}{cc} {x, \text { Number of Years }} & {y, \text { U.S. Population }} \\ {\text { after } 1969} & {\text { (millions) }} \\ {1(1970)} & {203.3} \\ {11(1980)} & {226.5} \\ {21(1990)} & {248.7} \\ {31(2000)} & {281.4} \\ {41(2010)} & {308.7} \end{array} $$ a. Use your graphing utility's exponential regression option to obtain a model of the form \(y=a b^{x}\) that fits the data. How well does the correlation coefficient, \(r,\) indicate that the model fits the data? b. Rewrite the model in terms of base \(e .\) By what percentage is the population of the United States increasing each year?

Determine whether each statement makes sense or does not make sense, and explain your reasoning. Because the equations $$\log (3 x+1)=5 \text { and } \log (3 x+1)=\log 5$$ are similar, I solved them using the same method.

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