/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Solve each polynomial inequality... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each polynomial inequality in Exercises \(1-42\) and graph the solution set on a real number line. Express each solution set in interval notation. $$ x^{2}-6 x+9<0 $$

Short Answer

Expert verified
The solution set in interval notation is \((- \infty, 3) \cup (3, +\infty)\)

Step by step solution

01

Factor the Polynomial

In order to find the roots of the quadratic, begin by factoring the equation \(x^2 - 6x + 9\). Since it's a perfect square trinomial, factoring yields \((x-3)^2\).
02

Find Roots of the Polynomial

Setting \((x-3)^2\) equal to zero, and solving for x gives the root \(x=3\).
03

Test Intervals

Now, choose a number from each of the intervals \(-\infty, 3\) and \(3, +\infty\) and check it in the inequality \(x^2 - 6x + 9 < 0\). If the inequality is true, the entire interval is included in our solution. For \(x<3\), let's choose \(x=0\) as the test point. Substituting \(x=0\) in the inequality yields \(9 > 0\), which is true. For \(x>3\), choose \(x=4\) as the test point. Substituting \(x=4\) gives \(-7 < 0\), which is also true. However, since our original inequality is strict (i.e., it doesn't include equal to), the root \(x=3\) itself doesn't satisfy the inequality.
04

Write Solution in Interval Notation

As a result, you can write the solution set as \(-\infty, 3\) and \(3, +\infty\), or \((- \infty, 3) \cup (3, +\infty)\) in interval notation.
05

Graph the Solution

On a number line, show these ranges by shading everything to the left of \(3\) not including \(3\) itself and everything to right of \(3\) not including \(3\) itself.

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