/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Solve each inequality in Exercis... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve each inequality in Exercises \(65-70\) and graph the solution set on a real number line. $$ \left|x^{2}+2 x-36\right|>12 $$

Short Answer

Expert verified
The solutions to the inequality are \( x < -8\) and \( x > 6\).

Step by step solution

01

Remove the Absolute Value

Considering the nature of absolute value, the equation will be broken down into two separate equations. These will be: \(x^2 + 2x - 36 > 12\) and also \(x^2 + 2x - 36 < -12\).
02

Solve Each Inequality

First solve \(x^2 + 2x - 36 > 12\). This simplifies to \(x^2 + 2x - 48 > 0\). Factoring the quadratic equation, \( (x - 6)(x + 8) > 0\). Setting the factors equal to zero gives two critical points, \( x = 6\) and \( x = -8\) which divide the number line into three regions. Test a point in each area to see where the inequality is satisfied. The second inequality \(x^2 + 2x - 36 < -12\) has no solution because a squared term is always positive and cannot be less than a negative value.
03

Graph the Solution on a Real Number Line

Graphing the solutions -8 and 6 from the first inequality on a number line, solutions exist in the regions where the first inequality is true, corresponding to the intervals \( (-\infty, -8) \) and \( (6, \infty) \).

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Most popular questions from this chapter

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Explain the relationship between the degree of a polynomial function and the number of turning points on its graph.

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