/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 What is the slope of a line that... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is the slope of a line that is perpendicular to the line whose equation is \(A x+B y+C=0, A \neq 0\) and \(B \neq 0 ?\)

Short Answer

Expert verified
The slope of the line that is perpendicular to the given line is \(B/A\).

Step by step solution

01

Expressing the given line in slope-intercept form

To find the slope, it is necessary to rewrite the equation in the form \(y = mx + c\). By doing so, m, the coefficient of x, will represent the slope of the given line. We can rearrange the given equation \(Ax + By + C = 0\) to \(y = -Ax/B - C/B\)
02

Identifying the slope of the given line

The slope of the given line will be \(-A/B\) as it corresponds to the coefficient of x in the slope-intercept form.
03

Finding the perpendicular slope

The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line. If the slope of a given line is m, the slope of the line perpendicular to it will be -1/m. Thus, the slope of the line perpendicular to our given line is \(-1/(-A/B) = B/A\).

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