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Chapter 2: Problem 26

Find the midpoint of each line segment with the given endpoints. $$\left(-\frac{2}{5}, \frac{7}{15}\right) \text { and }\left(-\frac{2}{5},-\frac{4}{15}\right)$$

Short Answer

Expert verified
The midpoint of the given line segment is at (-2/5, 1/30).

Step by step solution

01

Identify the coordinates of the endpoints

The two endpoints are (-2/5, 7/15) and (-2/5, -4/15). So, x1 = -2/5, y1 = 7/15 and x2 = -2/5, y2 = -4/15.
02

Apply the Midpoint Formula

Substitute the values of x1, y1, x2 and y2 in the midpoint formula. The midpoint M would be \((\frac{x1 + x2}{2}, \frac{y1 + y2}{2}) = (\frac{-2/5 + -2/5}{2}, \frac{7/15 + -4/15}{2})\).
03

Simplify the expressions

Simplify the expressions to get the coordinates of the midpoint. This gives us \((-2/5, 1/30)\).

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Most popular questions from this chapter

Solve: $$5 x^{\frac{3}{4}}-15=0$$ (Section 1.6, \text { Example } 5).

Solve and check: \(\frac{x-1}{5}-\frac{x+3}{2}=1-\frac{x}{4}\) (Section \(1.2, \text { Example } 3)\)

Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$x^{2}+y^{2}+3 x+5 y+\frac{9}{4}=0$$

Solve for \(y: \quad x=\frac{5}{y}+4\)

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