/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 An election ballot asks voters t... [FREE SOLUTION] | 91Ó°ÊÓ

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An election ballot asks voters to select three city commissioners from a group of six candidates. In how many ways can this be done?

Short Answer

Expert verified
A voter can make a total of 20 different selections from the six candidates.

Step by step solution

01

Understand the Formula for Combinations

The formula for calculating combinations is: \(C(n, r) = \frac{n!}{r!(n-r)!}\) where \(C(n, r)\) are the combinations, n is the total number of items, r is the number of items to choose, and '!' denotes a factorial.
02

Substitute into the Formula

Here, the number of candidates n is 6, and the number of city commissioners to select r is 3. Substitute these values into the combination formula: \(C(6, 3) = \frac{6!}{3!(6-3)!}\)
03

Simplify the Factorials

The factorials in the equation: 6! = 6 x 5 x 4 x 3 x 2 x 1 = 720, 3! = 3 x 2 x 1 = 6, and (6-3)! = 3! = 6.
04

Calculate the Combination

Replace the factorial values in the combination formula and calculate: \(C(6, 3) = \frac{720}{6 x 6} = 20\)

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