/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Use the Binomial Theorem to expa... [FREE SOLUTION] | 91Ó°ÊÓ

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Use the Binomial Theorem to expand each binomial and express the result in simplified form. $$ (2 a+b)^{6} $$

Short Answer

Expert verified
The expanded form of \((2a + b)^6\) is \(64a^6 + 192a^5b + 240a^4b^2 + 160a^3b^3 + 60a^2b^4 + 12ab^5 + b^6\).

Step by step solution

01

Understanding the Binomial Theorem

The Binomial Theorem tells us how to expand a binomial raised to a certain power. For any natural number \( n \), and any real numbers \( a \) and \( b \), \((a+b)^n = \sum_{k=0}^{n} {n\choose k} a^{n-k}b^{k}\).
02

Application of the Binomial Theorem

Now we put \( a \) as \( 2a \), \( b \) as \( b \), and \( n \) as \( 6 \) into the formula given by the Binomial Theorem. Following the formula, we find the expansion of \((2a + b)^6\) to be \(\sum_{k=0}^{6} {6\choose k} (2a)^{6-k} b^{k}\).
03

Calculation and Simplification

Applying the equation from step 2, it becomes: \({6\choose0} (2a)^6 b^0 + {6\choose1} (2a)^5 b^1 + {6\choose2} (2a)^4 b^2 + {6\choose3} (2a)^3 b^3 + {6\choose4} (2a)^2 b^4 + {6\choose5} (2a)^1 b^5 + {6\choose6} (2a)^0 b^6\). This simplifies to \(64a^6 + 192a^5b + 240a^4b^2 + 160a^3b^3 + 60a^2b^4 + 12ab^5 + b^6\).

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