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find the standard form of the equation of each hyperbola satisfying the given conditions. $$ \text { Foci: }(0,-3),(0,3) ; \text { vertices: }(0,-1),(0,1) $$

Short Answer

Expert verified
The standard form of the equation of the hyperbola is \(y^2/9 - x^2 = 1\)

Step by step solution

01

Identify a and b

From the provided vertices (0,-1) and (0,1), the value for 'a' can be found as the distance from the centre to the vertex, resulting in a=1. From the provided foci (0,-3) and (0,3), the value for 'b' can be found as the distance from the centre to the foci, resulting in b=3.
02

Substitute values

Substitute the values found for 'a' and 'b' into the general formula for a vertical hyperbola, i.e. \[ y^2/b^2 - x^2/a^2 = 1 \]. This gives: \[ y^2/3^2 - x^2/1^2 = 1 \] .
03

Simplify the equation

Simplify the equation given by: \[ y^2/9 - x^2 = 1 \], this simplifies to: \[ y^2/9 - x^2 = 1 \]. This is the standard form of the equation of the hyperbola.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conic Sections
Among the fascinating concepts in geometry are conic sections, which are the curves obtained by intersecting a plane with a double-napped cone. These shapes include circles, ellipses, parabolas, and hyperbolas. Interestingly, the angles at which the plane intersects the cone determine the type of conic section formed. For a hyperbola, the plane cuts through both naps of the cone, resulting in a shape comprised of two distinct, mirror-image curves. The general equation that represents any conic section, including hyperbolas, is given by the quadratic equation \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\), where the values and relationship among the coefficients A, B, and C determine the type of conic. Hyperbolas are defined by the condition \(B^2 - 4AC > 0\).

Understanding the general properties of conics is imperative because it allows students to easily categorize curves based on their equations and aids in recognizing the properties of these shapes, which have profound applications in physics, engineering, astronomy, and various other fields.
Foci of a Hyperbola
The foci of a hyperbola are two fixed points located along its axis of symmetry that play a crucial role in its geometric definition and properties. Unlike in ellipses, where the sum of the distances from the foci to any point on the ellipse is constant, for hyperbolas, the absolute difference in distances from any point on the hyperbola to its foci is constant. This property is known as the defining characteristic of a hyperbola.

In the given exercise, the foci are situated at (0,-3) and (0,3). Knowing the foci's coordinates is not only important in drawing a hyperbola but also in deriving the standard form equation of a hyperbola. The distance between the foci is given by \(2c\), and in this case, with the foci \(3\) units from the center on the y-axis, we calculated \(c = 3\). The value of \(c\) helps in determining the foci's coordinates and is also used in conjunction with \(a\) and \(b\) to establish the relationship \(c^2 = a^2 + b^2\) for hyperbolas.
Vertices of a Hyperbola
The vertices of a hyperbola are the points on each curve closest to the center, and they signify the 'tips' of the hyperbola. Identifying the vertices is key in defining the shape and dimensions of the hyperbola. In the standard equation of a hyperbola, \(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1\) for a horizontal hyperbola or \(\frac{y^2}{b^2} - \frac{x^2}{a^2} = 1\) for a vertical hyperbola, the parameter \(a\) is the distance from the center to a vertex along the primary axis of the hyperbola, which is the transverse axis.

The vertices provided in our exercise, at (0,-1) and (0,1), mean that the hyperbola opens vertically. With this information, we concluded that \(a = 1\). Knowing the position of the vertices enabled us to determine the values of \(a\) and \(b\), which are paramount in formulating the standard form of the hyperbola's equation. The coordinates of the vertices also aid in sketching the graph of the hyperbola, making them as essential as knowing the location of the foci.

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Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I can verify that \(2 x y-9=0\) is the equation of a hyperbola by rotating the axes through \(45^{\circ}\) or by showing that \(B^{2}-4 A C>0\)

Two fire-lookout stations are 10 miles apart with station B directly east of station A. Both stations spot a fire on a mountain to the north. The bearing from station A to the fire is N39°E (39° east of north). The bearing from station B to the fire is N42°W (42° west of north). How far, to the nearest tenth of a mile, is the fire from station A?

In Exercises \(61-66,\) find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. $$ \left\\{\begin{array}{r} {\frac{x^{2}}{25}+\frac{y^{2}}{9}=1} \\ {y=3} \end{array}\right. $$

a. Make a sketch of an angle \(\theta\) in standard position for which $$ \cot 2 \theta=-\frac{7}{24} \text { and } 90^{\circ}<2 \theta<180^{\circ} $$ b. Use your sketch from part (a) to determine the value of cos \(2 \theta\) c. Use the value of \(\cos 2 \theta\) from part (b) and the identities $$ \sin \theta=\sqrt{\frac{1-\cos 2 \theta}{2}} \text { and } \cos \theta=\sqrt{\frac{1+\cos 2 \theta}{2}} $$ to determine the values of \(\sin \theta\) and \(\cos \theta\) d. In part (c), why did we not write \(\pm\) before the radical in each formula?

In Exercises \(61-66,\) find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. $$ \left\\{\begin{array}{l} {x^{2}+y^{2}=1} \\ {x^{2}+9 y^{2}=9} \end{array}\right. $$

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