/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Factor each trinomial, or state ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor each trinomial, or state that the trinomial is prime. $$9 x^{2}+5 x-4$$

Short Answer

Expert verified
The factored form of the trinomial \(9x^2 + 5x - 4\) is \((9x - 4)(x + 1)\).

Step by step solution

01

Title

Set the trinomial. It is in the form of \(ax^2 + bx + c\), which we can identify as \(9x^2 + 5x - 4\).
02

Identify coefficients

From the trinomial, a=9, b=5 and c=-4.
03

Find two numbers

Find two numbers that multiply to (a*c) -36 and add up to b=5.
04

Break middle term

The two numbers are 9 and -4. Therefore, break down the middle term: Re-write \(9x^2 + 5x - 4\) as \(9x^2 + 9x - 4x - 4\).
05

Group and factor by GCF

Group the terms to become \(9x^2 + 9x + -4x - 4\) and factor by GCF within each binomial to get \(9x(x + 1) - 4(x + 1)\).
06

Factor out common binomial

There is a common binomial \((x + 1)\) within both the expressions which can be factored out and we get \((9x - 4)(x + 1)\).
07

Final form

Thus, the factored form of \(9x^2 + 5x - 4\) is \((9x - 4)(x + 1)\). If it was impossible to find terms that fulfill the criteria of step 3, then the trinomial would be considered prime, but that's not the case here.

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