/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 120 Use the order of operations to s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the order of operations to simplify each expression. $$\frac{12 \div 3 \cdot 5\left|2^{2}+3^{2}\right|}{7+3-6^{2}}$$

Short Answer

Expert verified
The simplified expression is -10.

Step by step solution

01

Simplify Inside Absolute Values and Parentheses

The first step according to BODMAS/BIDMAS principles is to simplify the expression inside the absolute value which also acts as parentheses or brackets. It includes powers or indices and addition. So we simplify \(2^{2}+3^{2}\) to get \(4 + 9 = 13\). And our expression becomes \(\frac{12 \div 3 \cdot 5\left|13\right|}{7+3-6^{2}}\)
02

Operate Upon Absolute Value

As our expression inside the absolute value is already a positive number, simply remove absolute value notation. So, the expression becomes \(\frac{12 \div 3 \cdot 5\cdot13}{7+3-6^{2}}\)
03

Simplify Division and Multiplication of Numerator

Following BODMAS/BIDMAS principles, first perform division, then multiplication in the numerator. Thus, \(\frac{12 \div 3 \cdot 5\cdot13}{7+3-6^{2}}\) simplifies to \(\frac{4 \cdot 5\cdot13}{7+3-6^{2}}\) and further to \(\frac{20\cdot13}{7+3-6^{2}}\) and finally we get \(\frac{260}{7+3-6^{2}}\)
04

Simplify Addition and Subtraction of Denominator

According to BODMAS/BIDMAS principles, perform addition first, then subtraction in the denominator. Thus, \(\frac{260}{7+3-6^{2}}\) simplifies to \(\frac{260}{10-6^{2}}\), then to \(\frac{260}{10-36}\) and finally we get \(\frac{260}{-26}\)
05

Divide Numerator by Denominator

Perform the division of numerator by denominator, therefore \(\frac{260}{-26} = -10\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.