Chapter 9: Problem 7
\(3-24=A\) pair of parametric equations is given. (a) Sketch the curve represented by the parametric equations. (b) Find a rectangular coordinate equation for the curve by eliminating the parameter. $$ X=\sqrt{t}, \quad y=1-t $$
Short Answer
Expert verified
The curve is a downward-opening parabola: \( y = 1 - X^2 \).
Step by step solution
01
Plot Points to Sketch the Curve
To sketch the curve represented by the parametric equations, first calculate a few points by substituting values for the parameter \(t\). Choose values such as \(t = 0, 1, 4\) for simplicity. - For \(t = 0\): \(X = \sqrt{0} = 0\) and \(y = 1 - 0 = 1\). The point is \((0, 1)\).- For \(t = 1\): \(X = \sqrt{1} = 1\) and \(y = 1 - 1 = 0\). The point is \((1, 0)\).- For \(t = 4\): \(X = \sqrt{4} = 2\) and \(y = 1 - 4 = -3\). The point is \((2, -3)\).Plot these points on the coordinate plane and draw the curve that passes through them.
02
Eliminate the Parameter to Find the Rectangular Equation
To eliminate the parameter and find a rectangular equation, express \(t\) in terms of \(X\) or \(y\), and substitute into the other equation. From \(X = \sqrt{t}\), solve for \(t\): \[ t = X^2 \]Substitute \(t = X^2\) into the equation for \(y\): \[ y = 1 - t = 1 - X^2 \]The rectangular equation is \( y = 1 - X^2 \).
03
Interpret the Rectangular Equation
The rectangular equation \( y = 1 - X^2 \) is that of a downward-opening parabola with its vertex at \((0, 1)\). The solution implies that the curve is a parabola, consistent with the parametric plot from Step 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eliminating the Parameter
Eliminating the parameter from parametric equations is a method to transition from a set of equations that define a curve in terms of a third variable, often labeled as \( t \), to a single equation in two variables, typically \( x \) and \( y \). For the given parametric equations \( X = \sqrt{t} \) and \( y = 1 - t \), eliminating the parameter involves solving one of these equations for \( t \) and substituting into the other equation.
To eliminate \( t \), first express \( t \) from \( X = \sqrt{t} \):
To eliminate \( t \), first express \( t \) from \( X = \sqrt{t} \):
- Solve for \( t \) to get \( t = X^2 \).
- The equation becomes \( y = 1 - X^2 \).
Rectangular Coordinate Equation
A rectangular coordinate equation, sometimes referred to as a Cartesian equation, is a traditional representation of curves in the coordinate plane, using two variables, usually \( x \) and \( y \). The goal is to write an equation that describes the same curve as represented by the given parametric equations without needing the third variable \( t \).
For the parametric equations \( X = \sqrt{t} \) and \( y = 1 - t \), the rectangular coordinate equation becomes \( y = 1 - X^2 \) after the elimination of the parameter was executed.
For the parametric equations \( X = \sqrt{t} \) and \( y = 1 - t \), the rectangular coordinate equation becomes \( y = 1 - X^2 \) after the elimination of the parameter was executed.
- This equation still describes the same curve but in a more unified form.
- It represents a clearer view of the relationship between \( x \) and \( y \), facilitating easier visualization and analysis of the curve.
Sketching Curves
Sketching curves from parametric equations is a foundational skill in understanding how different parameters influence a curve's shape and placement in the coordinate plane.
To sketch the curve:
To sketch the curve:
- Calculate several points from the parametric equations by substituting values for \( t \). For instance, when \( t = 0, 1, \) and \( 4 \), you get points \((0, 1)\), \((1, 0)\), \((2, -3)\).
- Plot these points on a coordinate plane.
- Draw a smooth curve through the plotted points to illustrate the curve's path.
Parabolas
A parabola is a specific type of curve that appears frequently in mathematics and physics, characterized by its "U" or inverted "U" shape. The general equation for a parabola found in the rectangular coordinate system is given by:
- Standard form: \( y = ax^2 + bx + c \).
- The parabola derived from the problem, \( y = 1 - X^2 \), is in the form \( y = -X^2 + 1 \).
- Understanding the vertex gives insight into the curve's "peak" or "trough" behavior.
- The negative sign before \( X^2 \) indicates the downward direction of the parabola.