/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 Verify the identity. $$ \fra... [FREE SOLUTION] | 91Ó°ÊÓ

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Verify the identity. $$ \frac{\csc ^{2} x-\cot ^{2} x}{\sec ^{2} x}=\cos ^{2} x $$

Short Answer

Expert verified
Identity verified: both sides equal \( \cos^{2} x \).

Step by step solution

01

Simplify the Left Side

The identity we need to verify is \( \frac{\csc^{2} x - \cot^{2} x}{\sec^{2} x} = \cos^{2} x \). First, we simplify the left side of the equation. Recall that \( \csc x = \frac{1}{\sin x} \) and \( \cot x = \frac{\cos x}{\sin x} \). Therefore, \( \csc^{2} x = \frac{1}{\sin^{2} x} \) and \( \cot^{2} x = \frac{\cos^{2} x}{\sin^{2} x} \). Thus, \( \csc^{2} x - \cot^{2} x = \frac{1}{\sin^{2} x} - \frac{\cos^{2} x}{\sin^{2} x} \). This simplifies to \( \frac{1 - \cos^{2} x}{\sin^{2} x} \).
02

Use Pythagorean Identity

Recall the Pythagorean identity: \( \sin^{2} x + \cos^{2} x = 1 \). Thus, \( 1 - \cos^{2} x = \sin^{2} x \). Substitute this in: \( \frac{\sin^{2} x}{\sin^{2} x} = 1 \).
03

Simplify the Denominator

In the original problem, the denominator of the left side is \( \sec^{2} x \), which is \( \frac{1}{\cos^{2} x} \). Substitute this into the expression: \( \frac{1}{\frac{1}{\cos^{2} x}} = \cos^{2} x \).
04

Verify the Equality

So the expression on the left becomes \( 1 \cdot \cos^{2} x = \cos^{2} x \), which matches the right side of the equation. The identity is verified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pythagorean Identity
The Pythagorean Identity is one of the fundamental relationships in trigonometry and can be expressed as \( \sin^{2} x + \cos^{2} x = 1 \). This simple yet powerful equation shows how sine and cosine are interconnected on the unit circle. It stems from the Pythagorean theorem applied to a right triangle where the hypotenuse is equal to 1.
This identity is crucial anytime you need to manipulate or simplify trigonometric expressions. In the given problem, we've applied it to transform \( 1 - \cos^{2} x \) into \( \sin^{2} x \).
  • It aids in simplifying equations involving squares of sine and cosine functions.
  • It can be rearranged to isolate other terms: e.g., \( \sin^{2} x = 1 - \cos^{2} x \).
  • It provides a way to check the rational combinations of trig functions for consistency.

By remembering this identity, you gain a powerful tool for solving various trigonometric equations and proving new identities without extensive computation.
Cosecant and Cotangent
Cosecant and cotangent are reciprocal trigonometric functions closely linked to sine and tangent, respectively. Understanding these functions is key to performing transformations on complex trigonometric identities.
  • \( \csc x = \frac{1}{\sin x} \) which means it is undefined whenever sine is zero.
  • \( \cot x = \frac{\cos x}{\sin x} \) stands as the ratio of cosine to sine.

For the identity \( \csc^2 x - \cot^2 x \), we use these definitions:
  • Transforming \( \csc^2 x \) to \( \frac{1}{\sin^2 x} \).
  • Transforming \( \cot^{2} x \) to \( \frac{\cos^{2} x}{\sin^{2} x} \).

This allows subtraction of the two fractions to aid in simplifying the expression. On the right path, knowing these identities makes solving, proving, and verifying trigonometric equations far more approachable.
Secant and Cosine
Secant and cosine are another pair of reciprocal trigonometric functions. Just like the previous pair, they provide alternative ways to express trigonometric equations.
  • \( \sec x = \frac{1}{\cos x} \), useful when cosine is non-zero.
  • The relationship helps in simplifying expressions involving these functions.

In our problem, we employed the relationship \( \sec^{2} x = \frac{1}{\cos^{2} x} \) to reframe the original equation's denominator.
This transformation:\[ \frac{\sec^{2} x}{1} = \frac{1}{\cos^{2} x} \text{ simplifies to just } \cos^{2} x.\]
Such simplifications are not only theoretically important but can ease computation. With consistent practice, converting between these functions becomes second nature, broadening the toolkit for tackling trigonometry challenges with confidence.

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Most popular questions from this chapter

\(35-38=(a)\) Graph \(f\) and \(g\) in the given viewing rectangle and find the intersection points graphically, rounded to two decimal places. (b) Find the intersection points of \(f\) and \(g\) algebraically. Give exact answers. $$ \begin{array}{l}{f(x)=\sin 2 x+1, g(x)=2 \sin 2 x+1} \\ {[-2 \pi, 2 \pi] \text { by }[-1.5,3.5]}\end{array} $$

\(17-34\) . An equation is given. (a) Find all solutions of the equation. (b) Find the solutions in the interval \([0,2 \pi) .\) $$ \tan 3 \theta+1=\sec 3 \theta $$

\(17-34\) . An equation is given. (a) Find all solutions of the equation. (b) Find the solutions in the interval \([0,2 \pi) .\) $$ 2 \sin \theta \tan \theta-\tan \theta=1-2 \sin \theta $$

\(35-38=(a)\) Graph \(f\) and \(g\) in the given viewing rectangle and find the intersection points graphically, rounded to two decimal places. (b) Find the intersection points of \(f\) and \(g\) algebraically. Give exact answers. $$ f(x)=\sin x-1, g(x)=\cos x,[-2 \pi, 2 \pi] \text { by }[-2.5,1.5] $$

Sound Beats When two pure notes that are close in frequency are played together, their sounds interfere to produce beats, that is, the loudness (or amplitude) of the sound alternately increases and decreases. If the two notes are given by $$f_{1}(t)=\cos 11 t \quad\( and \)\quad f_{2}(t)=\cos 13 t$$ the resulting sound is \(f(t)=f_{1}(t)+f_{2}(t)\) (a) Graph the function \(y=f(t)\) (b) Verify that \(f(t)=2 \cos t \cos 12 t\) (c) Graph \(y=2 \cos t\) and \(y=-2 \cos t,\) together with the graph in part \((a),\) in the same viewing rectangle. How do these graphs describe the variation in the loudness of the sound?

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