Chapter 8: Problem 48
\(47-50\) Find the exact value of the given expression. $$ \cos \left(2 \tan ^{-1} \frac{12}{5}\right) $$
Short Answer
Expert verified
The exact value is \(-\frac{119}{169}\).
Step by step solution
01
Identify the Inverse Tangent
The expression involves the inverse tangent, \( \tan^{-1} \frac{12}{5} \). Let's denote \(. Suppose \theta = \tan^{-1} \frac{12}{5}\). This means that \( \tan \theta = \frac{12}{5} \).
02
Use the Double Angle Formula for Cosine
The next step uses the double angle identity for cosine: \( \cos(2\theta) = 1 - 2\sin^2(\theta) \) or \(\cos(2\theta) = \cos^2(\theta) - \sin^2(\theta)\). Let's use \(\cos(2\theta) = 1 - 2\sin^2(\theta)\).
03
Calculate Sin and Cos Using a Right Triangle
Since \( \tan \theta = \frac{12}{5} \), create a right triangle where the opposite side is 12, and the adjacent side is 5. The hypotenuse \( h \) can be found using the Pythagorean Theorem: \( h = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13\).
04
Determine Values of Sin and Cos
From the triangle, \( \sin \theta = \frac{12}{13} \) and \( \cos \theta = \frac{5}{13} \).
05
Apply Values to the Double Angle Formula
Substitute the values found into the double angle formula: \( \cos(2\theta) = 1 - 2\left(\frac{12}{13}\right)^2 \).
06
Simplify the Expression
Compute \( \left(\frac{12}{13}\right)^2 = \frac{144}{169} \). Then multiply by 2: \( 2 \times \frac{144}{169} = \frac{288}{169}\).
07
Finalize the Expression
Thus, \( \cos(2\theta) = 1 - \frac{288}{169} = \frac{169}{169} - \frac{288}{169} = \frac{-119}{169}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cosine Double Angle Formula
The cosine double angle formula is a trigonometric identity that can simplify expressions involving angles. It's particularly useful in this problem, where we're dealing with a value of cosine for an angle that is twice another angle. There are three variations of this formula:
- \( \cos(2\theta) = \cos^2(\theta) - \sin^2(\theta) \)
- \( \cos(2\theta) = 2\cos^2(\theta) - 1 \)
- \( \cos(2\theta) = 1 - 2\sin^2(\theta) \)
Inverse Tangent
The inverse tangent function, also known as arctan, is used to find an angle whose tangent is a given number. In mathematical notation, if \( y = \tan^{-1}(x) \), then \( \tan(y) = x \). This is a powerful tool in trigonometry because it allows us to determine angles based on the ratio of two sides of a right triangle.
For example, in the given problem, \( \theta = \tan^{-1}\left(\frac{12}{5}\right) \). Here, \( x = 12/5 \) represents the opposite-over-adjacent ratio in a right triangle. By drawing or visualizing such a triangle, it becomes easier to understand how this function helps us determine angles from ratios.
For example, in the given problem, \( \theta = \tan^{-1}\left(\frac{12}{5}\right) \). Here, \( x = 12/5 \) represents the opposite-over-adjacent ratio in a right triangle. By drawing or visualizing such a triangle, it becomes easier to understand how this function helps us determine angles from ratios.
- Make a right triangle where the opposite side is 12 and the adjacent side is 5.
- Then use a trigonometric identity or a calculator to find the exact angle \( \theta \).
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in geometry that relates the lengths of the sides of a right triangle. The formula is \( a^2 + b^2 = c^2 \), where \( a \) and \( b \) are the legs of the triangle, and \( c \) is the hypotenuse, or the side opposite the right angle.
In this problem, the theorem is used to find the hypotenuse of a right triangle with sides 12 and 5:
In this problem, the theorem is used to find the hypotenuse of a right triangle with sides 12 and 5:
- Calculate \( h = \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13 \)