/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 \(37-42\) Find \(\sin \frac{x}{2... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(37-42\) Find \(\sin \frac{x}{2}, \cos \frac{x}{2},\) and \(\tan \frac{x}{2}\) from the given information. $$ \tan x=1, \quad 0^{\circ} < x < 90^{\circ} $$

Short Answer

Expert verified
\( x = 45^{\circ}, \sin \frac{x}{2} = \sqrt{\frac{\sqrt{2} - 1}{2}}, \cos \frac{x}{2} = \sqrt{\frac{\sqrt{2} + 1}{2}}, \tan \frac{x}{2} = \sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}} \).

Step by step solution

01

Identify the given function and angle

We are given that \( \tan x = 1 \) and the angle \( x \) is within the range \( 0^{\circ} < x < 90^{\circ} \). In this range, \( \tan x = 1 \) corresponds to \( x = 45^{\circ} \) since \( \tan 45^{\circ} = 1 \).
02

Use the half-angle identities

To find \( \sin \frac{x}{2}, \cos \frac{x}{2}, \text{and} \tan \frac{x}{2} \), use the half-angle identities:1. \( \sin \frac{x}{2} = \sqrt{\frac{1-\cos x}{2}} \)2. \( \cos \frac{x}{2} = \sqrt{\frac{1+\cos x}{2}} \)3. \( \tan \frac{x}{2} = \sqrt{\frac{1-\cos x}{1+\cos x}} \)
03

Calculate \( \cos x \)

Since \( x = 45^{\circ} \), we know \( \cos 45^{\circ} = \frac{\sqrt{2}}{2} \).
04

Compute \( \sin \frac{x}{2} \)

Substitute \( \cos 45^{\circ} = \frac{\sqrt{2}}{2} \) into the half-angle identity for sine:\[ \sin \frac{x}{2} = \sqrt{\frac{1 - \frac{\sqrt{2}}{2}}{2}} \]Compute:\[ \sin \frac{x}{2} = \sqrt{\frac{2 - \sqrt{2}}{4}} = \sqrt{\frac{\sqrt{2} - 1}{2}} \]
05

Compute \( \cos \frac{x}{2} \)

Substitute \( \cos 45^{\circ} = \frac{\sqrt{2}}{2} \) into the half-angle identity for cosine:\[ \cos \frac{x}{2} = \sqrt{\frac{1 + \frac{\sqrt{2}}{2}}{2}} \]Compute:\[ \cos \frac{x}{2} = \sqrt{\frac{2 + \sqrt{2}}{4}} = \sqrt{\frac{\sqrt{2} + 1}{2}} \]
06

Compute \( \tan \frac{x}{2} \)

Use the result from the identities:\[ \tan \frac{x}{2} = \frac{\sin \frac{x}{2}}{\cos \frac{x}{2}} \]This yields:\[ \tan \frac{x}{2} = \sqrt{\frac{\sqrt{2} - 1}{\sqrt{2} + 1}} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Angle Identities
When dealing with trigonometric functions, half-angle identities play a crucial role in simplifying and solving equations involving angles that are not easily calculated. These identities help us find the sine, cosine, and tangent of half an angle, which are especially useful when the original angle is known.
Half-angle identities for sine, cosine, and tangent are derived from double-angle formulas and provide valuable tools for trigonometric calculations. Here's a brief look at each half-angle identity:
  • For sine, the identity is \( \sin \frac{x}{2} = \sqrt{\frac{1 - \cos x}{2}} \).
  • The cosine identity is \( \cos \frac{x}{2} = \sqrt{\frac{1 + \cos x}{2}} \).
  • Tangent is represented as \( \tan \frac{x}{2} = \sqrt{\frac{1 - \cos x}{1 + \cos x}} \).
These formulas help in calculating values efficiently without needing direct computation of half-angles. Employing these identities reduces complex trigonometric expressions to more manageable forms, which is ideal for exercises, like finding the trigonometric value of half of a given angle.
Tangent Function
The tangent function is a fundamental concept in trigonometry, defined as the ratio of the opposite side to the adjacent side in a right triangle. Mathematically, it is expressed as \( \tan x = \frac{\sin x}{\cos x} \). This relationship allows us to calculate the tangent value when the sine and cosine are known.
In the range of \( 0^{\circ} < x < 90^{\circ} \), where our angle in this problem exists, tangent provides useful intersection values. For instance, at \( 45^{\circ} \), both sine and cosine are equal to \( \frac{\sqrt{2}}{2} \), making \( \tan 45^{\circ} = 1 \).
Knowing that the tangent of an angle equates to 1 can help identify the corresponding angle, which is crucial for exercises needing calculation of half-angle trigonometric values. It's important to understand that tangent's value is dependent on the angle and varies as the angle changes, being undefined at \( 90^{\circ} \) due to a zero denominator in the cosine function.
Sine and Cosine
Sine and cosine are foundational functions in trigonometry, often remembered as the sides of the right triangle. The functions are defined based on the unit circle, with sine representing the vertical coordinate and cosine the horizontal coordinate of a point where a terminal side of an angle intersects the circle.
Sine function, \( \sin x \), shows the ratio of the opposite side to the hypotenuse, whereas cosine, \( \cos x \), is the ratio of the adjacent side to the hypotenuse. In a unit circle, these ratios can be seen as projections of the radius along the y-axis and x-axis, respectively.
  • \( \sin 45^{\circ} = \frac{\sqrt{2}}{2} \)
  • \( \cos 45^{\circ} = \frac{\sqrt{2}}{2} \)
Understanding these fundamental trigonometric functions and their relation in a right triangle is vital for applying half-angle identities and manipulating expressions to find unknown values. These values also help in calculating related trigonometric identities, such as half-angle identities, further demonstrating their versatility in solving trigonometric equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Interference Two identical tuning forks are struck, one a fraction of a second after the other. The sounds produced are modeled by \(f_{1}(t)=C \sin \omega t\) and \(f_{2}(t)=C \sin (\omega t+\alpha) .\) The two sound waves interfere to produce a single sound modeled by the sum of these functions $$ f(t)=C \sin \omega t+C \sin (\omega t+\alpha) $$ (a) Use the Addition Formula for Sine to show that \(f\) can be written in the form \(f(t)=A \sin \omega t+B \cos \omega t,\) where \(A\) and \(B\) are constants that depend on \(\alpha\) . (b) Suppose that \(C=10\) and \(\alpha=\pi / 3 .\) Find constants \(k\) and \(\phi\) so that \(f(t)=k \sin (\omega t+\phi)\)

Sawing a Wooden Beam A rectangular beam is to be cut from a cylindrical log of diameter 20 in. (a) Show that the cross-sectional area of the beam is modeled by the function $$A(\theta)=200 \sin 2 \theta$$ where \(\theta\) is as shown in the figure. (b) Show that the maximum cross-sectional area of such a beam is \(200 \mathrm{in}^{2} .\) [Hint: Use the fact that sin \(u\) achieves its maximum value at \(u=\pi / 2.1\)

(a) Graph \(f(x)=\cos 2 x+2 \sin ^{2} x\) and make a conjecture. (b) Prove the conjecture you made in part (a).

Graphs and Identities Suppose you graph two functions, \(f\) and \(g,\) on a graphing device and their graphs appear identical in the viewing rectangle. Does this prove that the equation \(f(x)=g(x)\) is an identity? Explain.

Addition Formula for Tangent Use the Addition Formulas for Cosine and Sine to prove the Addition Formula for Tangent. [Hint: Use $$ \tan (s+t)=\frac{\sin (s+t)}{\cos (s+t)} $$ and divide the numerator and denominator by \(\cos s \cos t ]\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.