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\(3-10=\) Find the exact value of each expression, if it is defined. $$ \begin{array}{lll}{\text { (a) } \tan ^{-1} 0} & {\text { (b) } \tan ^{-1}(-\sqrt{3})} & {\text { (c) } \tan ^{-1}\left(-\frac{\sqrt{3}}{3}\right)}\end{array} $$

Short Answer

Expert verified
(a) 0, (b) \(-\frac{\pi}{3}\), (c) \(-\frac{\pi}{6}\)

Step by step solution

01

Understand the Problem

We need to find the exact values of the inverse tangent (arctangent) for different inputs. The inverse tangent function, denoted as \(\tan^{-1}(x)\), returns angles whose tangent is \(x\). These angles are typically in the range \([-\frac{\pi}{2}, \frac{\pi}{2}]\).
02

Solve Part (a) \(\tan^{-1}(0)\)

The tangent of 0 is 0. Thus, \(\tan^{-1}(0) = 0\) because the angle whose tangent is 0 within the range \([-\frac{\pi}{2}, \frac{\pi}{2}]\) is 0.
03

Solve Part (b) \(\tan^{-1}(-\sqrt{3})\)

We look for an angle \(\theta\) such that \(\tan(\theta) = -\sqrt{3}\). The reference angle with \(\tan(\theta) = \sqrt{3}\) is \(\frac{\pi}{3}\). Therefore, \(\tan^{-1}(-\sqrt{3})\) is in the fourth quadrant at \(\theta = -\frac{\pi}{3}\).
04

Solve Part (c) \(\tan^{-1}\left(-\frac{\sqrt{3}}{3}\right)\)

We seek an angle \(\theta\) such that \(\tan(\theta) = -\frac{\sqrt{3}}{3}\). The reference angle with \(\tan(\theta) = \frac{\sqrt{3}}{3}\) is \(\frac{\pi}{6}\). Thus, \(\tan^{-1}\left(-\frac{\sqrt{3}}{3}\right) = -\frac{\pi}{6}\) because it lies in the fourth quadrant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Inverse Tangent
The inverse tangent function, also known as arctangent and denoted as \( \tan^{-1}(x) \), is a vital tool in trigonometry for finding an angle when the tangent of that angle is given. This function helps you determine angles from the ratio of the opposite side to the adjacent side in a right-angled triangle.
When you use \( \tan^{-1}(x) \), you obtain an angle \( \theta \) such that \( \tan(\theta) = x \). It is important to remember the range of the inverse tangent function, which is from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\). This range ensures that for every possible value of \( x \), there is a unique angle \( \theta \).
  • If \( x = 0 \), \( \tan^{-1}(0) = 0 \) reflects directly the angle whose tangent is 0.
  • For negative values like \( \tan^{-1}(-\sqrt{3}) \), your resulting angle will lie between \(-\frac{\pi}{2}\) and 0.
Understanding these properties allows you to accurately find angles when given specific tangent values.
Finding Reference Angles
Reference angles are essential in solving trigonometric functions, especially when dealing with angles greater than \(90^\circ\) or in different quadrants. A reference angle is the acute angle that a given angle makes with the x-axis. Knowing this angle helps in evaluating trigonometric functions, such as tangent, in various quadrants.
When you find \( \tan^{-1}(x) \) for values such as \(-\sqrt{3} \) or \(-\frac{\sqrt{3}}{3} \), your goal is to locate the reference angle first. For example, the reference angle of \( \theta \) that satisfies \( \tan(\theta) = \sqrt{3} \) is \( \frac{\pi}{3} \). For its negative counterpart, such as \( \tan(\theta) = -\sqrt{3} \), the angle \( \theta \) will be \( -\frac{\pi}{3} \) in the fourth quadrant.
  • It simplifies the calculation by allowing you to focus on a known, related angle.
  • By using reference angles, you can find equivalent angles in other quadrants.
Reference angles thereby provide a clear method for evaluating angle measures with inverse trigonometric functions.
Exploring Trigonometric Identities
Trigonometric identities play a crucial role in simplifying expressions and solving equations involving trigonometric functions. They allow you to relate different trigonometric functions together and solve for unknown angles or sides in triangles.
Some fundamental identities you often use include the Pythagorean identity, angle sum and difference identities, and co-function identities. When dealing with inverse tangent functions, it can be useful to recall how a change in sign or angle reflects movement across different quadrants.
For example, knowing that \( \tan(\theta) = \frac{1}{\tan(\theta)} \) for \( \theta \) moving from one quadrant to another can help determine solutions to inverse trigonometric functions in exercises like finding \( \tan^{-1}\left( -\frac{\sqrt{3}}{3} \right) \).
  • Utilizing these identities allows you to work backward from complex angles.
  • They provide strategies for manipulating and solving trigonometric expressions.
Thus, trigonometric identities are powerful tools in enhancing your problem-solving skills in trigonometry.

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