Chapter 7: Problem 53
Find the period and graph the function. $$ y=-2 \tan \left(2 x-\frac{\pi}{3}\right) $$
Short Answer
Expert verified
Period is \( \frac{\pi}{2} \); graph is a stretched, reflected tan function.
Step by step solution
01
Identify the standard form of tan function
The standard form of a tangent function is \( y = A \tan(Bx - C) + D \). In this problem, the function \( y = -2 \tan\left(2x - \frac{\pi}{3}\right) \) corresponds to \( A = -2 \), \( B = 2 \), \( C = \frac{\pi}{3} \), and \( D = 0 \).
02
Determine the period of the tangent function
The period of the tangent function \( y = A \tan(Bx - C) + D \) is given by \( \frac{\pi}{B} \). For this function, \( B = 2 \), so the period is \( \frac{\pi}{2} \).
03
Find the phase shift
The phase shift is calculated using \( \frac{C}{B} \). Substituting \( C = \frac{\pi}{3} \) and \( B = 2 \), the phase shift is \( \frac{\frac{\pi}{3}}{2} = \frac{\pi}{6} \). This means the graph is shifted to the right by \( \frac{\pi}{6} \).
04
Analyze vertical stretch and reflection
The vertical stretch factor is \( |A| = 2 \), and since \( A = -2 \), the graph is reflected across the x-axis.
05
Graph the function
To graph \( y = -2 \tan(2x - \frac{\pi}{3}) \), follow these steps:1. Start with the tangent function \( y = \tan x \).2. Apply the period change. The period is \( \frac{\pi}{2} \), so complete cycles occur between \( 0 \) and \( \frac{\pi}{2} \), etc.3. Implement the phase shift by shifting the function \( \frac{\pi}{6} \) to the right.4. Apply the vertical stretch by multiplying the output by 2.5. Reflect the graph across the x-axis, due to the \(-2\).Plot key points and asymptotes at \( x = \frac{\pi}{12}, \frac{\pi}{4}, ... \) and graph accordingly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Period of Tangent Function
The period of a function tells us how often the function repeats itself. For tangent functions, this is a straightforward concept. The standard period for the tangent function \( y = \tan(x) \) is \( \pi \). However, our problem involves an altered tangent function: \( y = -2 \tan(2x - \frac{\pi}{3}) \). To find the period of such a function, we use the formula \( \frac{\pi}{B} \), where \( B \) is the coefficient of \( x \) inside the function.
In this function, \( B = 2 \). Therefore, substituting the value in the formula gives us:
In this function, \( B = 2 \). Therefore, substituting the value in the formula gives us:
- Period = \( \frac{\pi}{2} \)
Phase Shift
Phase shift refers to the horizontal movement of a function along the x-axis. It's influenced by the \( C \) value in the transformation form \( y = A \tan(Bx - C) + D \). For the given function \( y = -2 \tan(2x - \frac{\pi}{3})\), the phase shift is calculated by \( \frac{C}{B} \).
Here, we have:
The positive result indicates that the graph of our tangent function shifts \( \frac{\pi}{6} \) units to the right. It's important for locating the starting point of the function's cycle on the graph.
Here, we have:
- \( C = \frac{\pi}{3} \)
- \( B = 2 \)
The positive result indicates that the graph of our tangent function shifts \( \frac{\pi}{6} \) units to the right. It's important for locating the starting point of the function's cycle on the graph.
Vertical Stretch
The vertical stretch in a tangent function affects how much the graph stretches or compresses vertically by a factor determined by \( A \). If \( |A| > 1 \), it means the function's graph is stretched, making it taller, while \( |A| < 1 \) would compress it, making it shorter.
For our function \( y = -2 \tan(2x - \frac{\pi}{3}) \), \( A = -2 \), giving a stretch factor of \( |A| = 2 \).
For our function \( y = -2 \tan(2x - \frac{\pi}{3}) \), \( A = -2 \), giving a stretch factor of \( |A| = 2 \).
- This means every point on the tangent curve is twice as far from the x-axis as it would be in the parent graph of \( y = \tan(x) \).
Reflection Across X-Axis
Reflection is one way a function's graph can be transformed. In particular, a reflection across the x-axis inverts all y-values of the function. This occurs in our function due to the negative sign in the \( A \) value.
Given the function \( y = -2 \tan(2x - \frac{\pi}{3}) \), the negative sign before the 2 (i.e., \( A = -2 \)) indicates:
Given the function \( y = -2 \tan(2x - \frac{\pi}{3}) \), the negative sign before the 2 (i.e., \( A = -2 \)) indicates:
- All positive y-values of a corresponding point in the parent graph become negative.
- All negative y-values of a corresponding point in the parent graph become positive.