/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Graph both functions on one set ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Graph both functions on one set of axes. $$ f(x)=4^{x} \quad \text { and } \quad g(x)=7^{x} $$

Short Answer

Expert verified
Graph the exponential functions: \( f(x) = 4^x \) grows slower than \( g(x) = 7^x \).

Step by step solution

01

Understand the Functions

The functions given are exponential functions. The function \( f(x) = 4^x \) means the base is 4 and the variable is in the exponent. Similarly, \( g(x) = 7^x \) has a base of 7.
02

Identify Key Points

Identify a few key points for each function. For example:- For \( f(x) = 4^x \), we have: \( f(0) = 1 \), \( f(1) = 4 \), \( f(2) = 16 \), \( f(-1) = 1/4 \).- For \( g(x) = 7^x \), we have: \( g(0) = 1 \), \( g(1) = 7 \), \( g(2) = 49 \), \( g(-1) = 1/7 \).
03

Plot the Functions

Using the key points identified, plot both functions on the same graph. The x-axis should have values ranging from negative to positive, while the y-axis should be scaled to include the range of values produced by both functions.
04

Analyze the Graph

Both functions will pass through the point (0,1) because anything raised to the power of zero is 1. Further, since 7 is greater than 4, \( g(x) = 7^x \) will grow faster than \( f(x) = 4^x \). The graph of \( g(x) \) should be steeper than that of \( f(x) \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Exponential Functions
Exponential functions are special because they show repeated multiplication. Understanding how they work is the first step to mastering them. When graphing, these functions create a curve that either rises or falls dramatically.

The functions we have, \(f(x) = 4^x\) and \(g(x) = 7^x\), are exponential because the variable \(x\) is in the exponent.
Consider how the graphs of \(y = b^x \) typically behave:
  • For \(x = 0\), any base \(b\) results in a value of 1.This is why both functions pass through the point \((0, 1)\).
  • If \(b > 1\), the function grows rapidly.The larger the base, the steeper the graph.This means \(g(x) = 7^x\) will be steeper than \(f(x) = 4^x\).
To graph these functions, choose a range of \(x\)-values and calculate corresponding \(y\)-values. Connect these points smoothly to form a curve.
Key Points Identification
Identifying key points can make graphing easier. These act as anchor points that help define the curve of the graph. For exponential functions, key points include: \(x = 0, 1, 2, -1, -2, \) and so on. Each has a specific value based on our functions.
  • For \(f(x) = 4^x\):
    • \(f(0) = 1\)
    • \(f(1) = 4\)
    • \(f(2) = 16\)
    • \(f(-1) = 1/4\)
  • For \(g(x) = 7^x\):
    • \(g(0) = 1\)
    • \(g(1) = 7\)
    • \(g(2) = 49\)
    • \(g(-1) = 1/7\)
These points give clarity on how the graphs will look.Compare these points across both functions to predict which grows faster or by how much.
Remember, the graphs also approach zero but never quite reach it as \(x\) becomes very negative.
Function Analysis
Let's dive into analyzing these exponential graphs. Seeing them side by side reveals important differences between \(f(x)\) and \(g(x)\).Examining the plot of both functions shows that:
  • Both exponential functions intersect the y-axis at \((0,1)\).
  • \(g(x) = 7^x\) grows faster than \(f(x) = 4^x\).This is because the base 7 is greater than base 4.Hence the steeper graph.
These observations confirm:
  • A higher base in an exponential function equates to a steeper increase.
  • Exponential functions are key in modeling rapid growth scenarios, like population or bank interest.
Understanding how their growth differs helps in solving real-world problems and choosing the right model for various data sets.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw the graph of the function in a suitable viewing rec- tangle, and use it to find the domain, the asymptotes, and the local maximum and minimum values. $$ y=x(\ln x)^{2} $$

Difficulty of a Task The difficulty in "acquiring a target" such as using your mouse to click on an icon on your computer screen) depends on the distance to the target and the size of the target. According to Fits's Law, the index of difficulty (ID) is given by $$ \mathrm{ID}=\frac{\log (2 A / W)}{\log 2} $$ where \(W\) is the width of the target and \(A\) is the distance to the center of the target. Compare the difficulty of clicking on an icon that is 5 \(\mathrm{mm}\) wide to clicking on one that is 10 \(\mathrm{mm}\) wide. In each case, assume that the mouse is 100 \(\mathrm{mm}\) from the icon.

Population of California The population of California was 29.76 million in 1990 and 33.87 million in 2000 . Assume that the population grows exponentially. (a) Find a function that models the population \(t\) years after 1990 . (b) Find the time required for the population to double. (c) Use the function from part (a) to predict the popuble. California in the year 2010 . Look up California's actual population in 2010 , and compare.

\(25-28=\) These exercises use Newton's Law of Cooling. Cooling Soup A hot bowl of soup is served at a dinner party. It starts to cool according to Newton's Law of Cooling, so its temperature at time \(t\) is given by $$ T(t)=65+145 e^{-0.05 t} $$ where \(t\) is measured in minutes and \(T\) is measured in \(^{\circ} \mathrm{F}\) . (a) What is the initial temperature of the soup? (b) What is the temperature after 10 \(\mathrm{min}\) ? (c) After how long will the temperature be \(100^{\circ} \mathrm{F} ?\)

A learning curve is a graph of a function \(P(t)\) that measures the performance of someone learning a skill as a function of the training time \(t\) . At first, the rate of learning is rapid. Then, as performance increases and approaches a maximal value \(M\) , the rate of learning decreases. It has been found that the function $$P(t)=M-C e^{-k t}$$ where \(k\) and \(C\) are positive constants and \(C< M\) is a reasonable model for learning. (a) Express the learning time \(t\) as a function of the performance level \(P .\) (b) For a pole-vaulter in training, the learning curve is given by $$P(t)=20-14 e^{-0.024 t}$$ where \(P(t)\) is the height he is able to pole-vault after \(t\) months. After how many months of training is he able to vault 12 \(\mathrm{ft}\) ? (c) Draw a graph of the learning curve in part (b).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.