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Find the slant asymptote, the vertical asymptotes, and sketch a graph of the function. $$ r(x)=\frac{x^{3}+4}{2 x^{2}+x-1} $$

Short Answer

Expert verified
Slant asymptote: \(y = \frac{1}{2}x\); vertical asymptotes: \(x = \frac{1}{2}\) and \(x = -1\).

Step by step solution

01

Identify the Degree of Numerator and Denominator

First, look at the degrees of the numerator and the denominator of the function. The numerator is \(x^3+4\), which has a degree of 3, and the denominator is \(2x^2+x-1\), which has a degree of 2.
02

Determine the Existence of a Slant Asymptote

Since the degree of the numerator (3) is one more than the degree of the denominator (2), a slant asymptote exists for the given rational function.
03

Long Division to Find the Slant Asymptote

Perform polynomial long division of \(x^3 + 4\) by \(2x^2 + x - 1\). This division will give you the equation of the slant asymptote. The quotient is \(\frac{1}{2}x\) with a remainder. Thus, the slant asymptote is \(y = \frac{1}{2}x\).
04

Set Denominator Equal to Zero to Find Vertical Asymptotes

To find the vertical asymptotes, set the denominator equal to zero: \[ 2x^2 + x - 1 = 0 \]Use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = 2, b = 1, c = -1\). This gives results: \(x = \frac{-1 \pm \sqrt{9}}{4}\), leading to vertical asymptotes at \(x = \frac{1}{2}\) and \(x = -1\).
05

Prepare to Sketch the Graph

Consider the slant asymptote, \(y = \frac{1}{2}x\), and the vertical asymptotes, \(x = \frac{1}{2}\) and \(x = -1\). The slant asymptote suggests the behavior as \(x\) approaches infinity and negative infinity. The vertical asymptotes indicate points where the function is undefined, and near which the function will increase or decrease without bound.
06

Sketch the Rational Function

Based on all the details: sketch the function showing the slant asymptote approaching near infinity, and ensure the vertical asymptotes \(x = \frac{1}{2}\) and \(x = -1\) are where the function is undefined. Check a few points to see the curvature behavior around these asymptotes and draw the function accordingly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slant Asymptote
A slant asymptote, also known as an oblique asymptote, occurs in a rational function when the degree of the numerator is one more than that of the denominator. This means the graph of the function will approach a line that is neither horizontal nor vertical as x heads towards positive or negative infinity.

To find the slant asymptote for a given function, we perform polynomial long division on the function. For example, in the rational function \(r(x) = \frac{x^3+4}{2x^2+x-1}\), the numerator has a degree of 3, while the denominator has a degree of 2. By dividing \(x^3 + 4\) by \(2x^2 + x - 1\), we discovered that the slant asymptote is \(y = \frac{1}{2}x\). This line describes the end behavior of the function, indicating a linear trajectory as the function values grow large or small.
Vertical Asymptotes
Vertical asymptotes occur in a rational function wherever the denominator is zero and the numerator is non-zero at those points. They indicate that the function approaches positive or negative infinity as it gets closer to a certain x-value.

To identify vertical asymptotes in the function \(r(x) = \frac{x^3+4}{2x^2+x-1}\), we need to solve for when \(2x^2 + x - 1 = 0\). Using the quadratic formula, we find the solutions to be \(x = \frac{1}{2}\) and \(x = -1\). At these points, the function becomes undefined, and its value tends toward infinity.
  • For rational functions, each vertical asymptote corresponds to a root of the denominator that does not cancel with the numerator.
  • The curve on the graph will tend to rise or fall sharply as it approaches these x-values.
Polynomial Long Division
Polynomial long division is a technique used to divide polynomial expressions, similar to long division with numbers. It helps to find slant asymptotes or simplify expressions.

Let's use our example: divide \(x^3 + 4\) by \(2x^2 + x - 1\). Think of this as a way to "fit" the smaller polynomial into the larger one. We repeatedly divide the leading terms, subtract, and bring down the next terms, much like traditional long division.

The result for our function is \(\frac{1}{2}x\) with a remainder, suggesting that the non-remainder part forms the slant asymptote's equation: \(y = \frac{1}{2}x\).
  • This quotient (\(\frac{1}{2}x\)) approximates the behavior of the function graph as \(x\) heads to infinity.
  • The remainder in the division affects the approximation's accuracy but typically diminishes with larger x-values.
Rational Function Graphing
Graphing a rational function involves combining several aspects: the location of vertical and slant (or horizontal) asymptotes, x-intercepts, y-intercepts, and overall behavior.

For instance, with \(r(x) = \frac{x^3+4}{2x^2+x-1}\), we already discovered its slant asymptote \(y = \frac{1}{2}x\) and vertical asymptotes at \(x = \frac{1}{2}\) and \(x = -1\). These guides indicate the boundaries and directional tendencies of the function.
  • As \(x\) approaches each vertical asymptote, the graph should diverge to \(+\infty\) or \(-\infty\).
  • As \(x\) approaches \(+\infty\) or \(-\infty\), the function approaches its slant asymptote.
  • Sketching the graph helps visualize these asymptotic behaviors.
  • Plot additional points near key features to verify the curve's shape and direction.

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Most popular questions from this chapter

A Rational Function with No Asymptote Explain how you can tell (without graphing it) that the function $$ r(x)=\frac{x^{6}+10}{x^{4}+8 x^{2}+15} $$ has no \(x\) -intercept and no horizontal, vertical, or slant asymptote. What is its end behavior?'

There are two square roots of \(1,\) namely, 1 and \(-1 .\) These are the solutions of \(x^{2}=1 .\) The fourth roots of 1 are the solutions of the equation \(x^{4}=1\) or \(x^{4}-1=0 .\) How many fourth roots of 1 are there? Find them. The cube roots of 1 are the solutions of the equation \(x^{3}=1\) or \(x^{3}-1=0\) . How many cube roots of 1 are there? Find them. How would you find the sixth roots of 1\(?\) How many are there? Make a conjecture about the number of \(n\) th roots of \(1 .\)

Use a graphing device to find all real solutions of the equation, rounded to two decimal places. $$ 4.00 x^{4}+4.00 x^{3}-10.96 x^{2}-5.88 x+9.09=0 $$

A polynomial \(P\) is given. (a) Find all the real zeros of \(P\) (b) Sketch the graph of \(P\) . $$ P(x)=3 x^{3}+17 x^{2}+21 x-9 $$

How Many Real Zeros Can a Polynomial Have? Give examples of polynomials that have the following properties, or explain why it is impossible to find such a polynomial. (a) A polynomial of degree 3 that has no real zeros (b) A polynomial of degree 4 that has no real zeros (c) A polynomial of degree 3 that has three real zeros, only one of which is rational (d) \(\mathrm{A}\) polynomial of degree 4 that has four real zeros, none of which is rational What must be true about the degree of a polynomial with integer coefficients if it has no real zeros?

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