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Find the slant asymptote, the vertical asymptotes, and sketch a graph of the function. $$ r(x)=\frac{x^{2}+2 x}{x-1} $$

Short Answer

Expert verified
The slant asymptote is \( y = x + 3 \) and the vertical asymptote is \( x = 1 \).

Step by step solution

01

Simplify the Function

Given the rational function \( r(x) = \frac{x^2 + 2x}{x - 1} \), we need to divide the numerator by the denominator to identify any slant asymptote. Use polynomial long division to divide \( x^2 + 2x \) by \( x - 1 \).
02

Perform Polynomial Long Division

Divide \( x^2 + 2x \) by \( x - 1 \):1. Divide the first term of the numerator \( x^2 \) by the first term of the denominator \( x \) to get \( x \).2. Multiply \( x \) by \( x - 1 \) to get \( x^2 - x \).3. Subtract \( x^2 - x \) from \( x^2 + 2x \) to get \( 3x \).4. Divide \( 3x \) by \( x \) to get \( 3 \).5. Multiply \( 3 \) by \( x - 1 \) to get \( 3x - 3 \).6. Subtract \( 3x - 3 \) from \( 3x \) to get \( 3 \).The quotient is \( x + 3 \) and the remainder is \( 3 \). Thus, \( r(x) = x + 3 + \frac{3}{x-1} \).
03

Identify the Slant Asymptote

The slant asymptote of a rational function occurs when the degree of the numerator is exactly one more than the degree of the denominator. In this case, it is the quotient from the division, \( y = x + 3 \).
04

Determine the Vertical Asymptote

Vertical asymptotes occur where the denominator is equal to zero and the numerator is non-zero. Set \( x - 1 = 0 \) to find \( x = 1 \). Since the remainder when divided doesn't affect divisibility, a vertical asymptote exists at \( x = 1 \).
05

Sketch the Graph

To sketch the graph:1. Plot the slant asymptote \( y = x + 3 \).2. Plot the vertical asymptote at \( x = 1 \).3. As \( x \to \pm \infty \), the function \( r(x) \to x + 3 \).4. Analyze the behavior near the vertical asymptote at \( x=1 \): - As \( x \) approaches 1 from the left, \( r(x) \to -\infty \). - As \( x \) approaches 1 from the right, \( r(x) \to \infty \).5. Include points such as the y-intercept: Substitute \( x = 0 \) into \( r(x) \) to find \( r(0) = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Asymptotes
Vertical asymptotes are an essential part of understanding rational functions. They occur at points where the function is undefined, primarily when the denominator of a fraction equals zero and the numerator isn't also zero at the same point.

In the case of the function \( r(x) = \frac{x^2 + 2x}{x - 1} \), our denominator is \( x - 1 \). Vertical asymptotes are found by setting the denominator equal to zero which, in this case, is solved by \( x - 1 = 0 \).

Upon solving, we get \( x = 1 \). Thus, a vertical asymptote exists at \( x = 1 \).

This means as \( x \) approaches 1 from either direction, the function \( r(x) \) will approach infinity or negative infinity depending on the side from which you approach. This is crucial behavior to note when sketching the graph of rational functions.
Polynomial Long Division
Polynomial long division is a method used to divide one polynomial by another. It's akin to regular long division that's taught in elementary mathematics, but applied to polynomials. This technique is important for finding slant asymptotes in rational functions where the degree of the numerator is greater than the degree of the denominator.

When we performed polynomial long division on \( x^2 + 2x \) divided by \( x - 1 \):
  • We divided \( x^2 \) by \( x \) and obtained \( x \).
  • We then multiplied \( x \) by \( x - 1 \), which gave us \( x^2 - x \), and subtracted it from \( x^2 + 2x \), leaving \( 3x \).
  • Next, \( 3x \) was divided by \( x \) to yield \( 3 \).
  • We multiplied \( 3 \) by \( x - 1 \) to get \( 3x - 3 \), and after subtraction, this left us with a remainder of 3.
Thus, \( r(x) \) can be expressed as \( x + 3 + \frac{3}{x-1} \). The outcome of the division is instrumental in determining the function's slant asymptote.
Rational Functions
Rational functions are ratios of polynomials, represented as \( f(x) = \frac{p(x)}{q(x)} \), where both \( p(x) \) and \( q(x) \) are polynomials and \( q(x) eq 0 \).

These functions are characterized by their asymptotic behavior, including vertical and slant asymptotes, and their unique graph shapes. Understanding how to manipulate and sketch them is a vital skill.

In \( r(x) = \frac{x^2 + 2x}{x - 1} \), the numerator \( x^2 + 2x \) and the denominator \( x - 1 \) tell us about the behavior of the function as \( x \) approaches various critical values.
  • Vertical asymptotes arise where the denominator zeroes out, unless the numerator is zero at these points too.
  • Slant asymptotes occur when the degree of the numerator is precisely one greater than that of the denominator, as is the case here.
Recognizing these aspects helps in graphing and understanding the potential behavior of any rational function.

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Most popular questions from this chapter

The Conjugate Zeros Theorem says that the complex zeros of a polynomial with real coefficients occur in complex conjugate pairs. Explain how this fact proves that a polynomial with real coefficients and odd degree has at least one real zero.

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