Chapter 4: Problem 66
A polynomial P is given. (a) Factor P into linear and irreducible quadratic factors with real coefficients. (b) Factor P completely into linear factors with complex coefficients. \(P(x)=x^{4}+8 x^{2}+16\)
Short Answer
Expert verified
(a) \((x^2 + 4)^2\) with real coefficients; (b) \((x - 2i)^2(x + 2i)^2\) with complex coefficients.
Step by step solution
01
Look for Common Factors
First, check if there are any common factors in the polynomial. For the polynomial \(P(x) = x^4 + 8x^2 + 16\), there aren't common factors across all terms, so we can proceed to factoring it as a sum of squares.
02
Identify Format for Factoring
Recognize the polynomial as a quadratic in terms of \(x^2\): \(x^4 + 8x^2 + 16 = (x^2 + 4)^2\). This conforms to the standard form for a polynomial where \((a+b)^2 = a^2 + 2ab + b^2\).
03
Factor Into Quadratic Form
Since \((x^2 + 4)^2 = (x^2 + 4)^2\), identify \(x^2 + 4\) as an irreducible quadratic over the reals. Thus, the polynomial is factored as \((x^2 + 4)(x^2 + 4)\) for real coefficients.
04
Factor Completely with Complex Numbers
To factor \(x^2 + 4\) completely into linear factors with complex coefficients, equate to zero: \(x^2 + 4 = 0\). Solve for \(x\) by rewriting it as \(x^2 = -4\), then \(x = \pm 2i\). Therefore, factor \(x^2 + 4\) as \((x - 2i)(x + 2i)\).
05
Apply Linear Factoring to Polynomial
Using the linear factors from the Step 4, fully factor \(P(x)\). Since each \(x^2 + 4\) factor becomes \((x - 2i)(x + 2i)\), the entire polynomial is \((x - 2i)(x + 2i)(x - 2i)(x + 2i)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Factors
Factoring a polynomial into linear factors means expressing it as a product of first-degree polynomials, each of which is called a linear factor. Linear factors are in the form of \((x - a)\), where \(a\) is any number (real or complex) that makes the factor equal to zero. For example, if \(P(x)\) has a root \(a\), then \((x-a)\) is a linear factor. In our exercise, we factor the polynomial \(P(x) = x^4 + 8x^2 + 16\) completely, first with complex coefficients. This means finding the roots of the polynomial equation and expressing each factor in a linear form.
- Start by solving \(x^2 + 4 = 0\).
- This yields roots \(x = 2i\) and \(x = -2i\).
- Then, the linear factors are \((x - 2i)\) and \((x + 2i)\).
Irreducible Quadratic
An irreducible quadratic over the real numbers is a quadratic polynomial that cannot be factored into linear factors with real coefficients. Quadratics in the form \(ax^2 + bx + c\) can sometimes be rewritten using real number coefficients, but occasionally they remain as an irreducible quadratic. In terms of the exercise, the polynomial \(x^2 + 4\) is irreducible over the reals because it has no real roots: its discriminant \(b^2 - 4ac = -16\) is negative. Thus, no factorization using real numbers allows it to be expressed as a product of two linear factors.
- Irreducible quadratics help in maintaining the integrity of polynomial representation over the reals.
- The polynomial \(x^2 + 4\) holds its form in real factorization as \((x^2 + 4)(x^2 + 4)\).
- They often suggest the presence of complex roots.
Complex Coefficients
Complex coefficients come into play when a polynomial cannot be expressed completely via real coefficients alone. These coefficients include imaginary numbers, typically utilized for full polynomial factorization. Imaginary numbers are based on \(i\), where \(i^2 = -1\), and are key in expressing roots of certain polynomials.For instance, in the given polynomial \(x^2 + 4\), by solving for \(x\) (i.e., \(x^2 = -4\)), you get \(x = \pm 2i\). Hence, the equation has complex roots and factors into linear terms with complex coefficients.
- Express polynomial as a multiplication of linear factors from their complex roots.
- These factors help understand the complete behavior of the polynomial in complex number terms.
- They demonstrate the vast landscape of solutions beyond just real-number results.
Real Coefficients
Real coefficients define polynomials adjustable to operations limited within the realm of real numbers. When a polynomial is said to have real coefficients, it means that each term's coefficient is a real number. This condition sets a boundary where factorization must remain within the real number scope unless specified to open to complex numbers. In the context of the exercise, the initial goal is to factor \(P(x) = x^4 + 8x^2 + 16\) into terms acceptable under real numbers. Hence, it's expressed as \((x^2 + 4)(x^2 + 4)\), a representation signaling irreducibility in the real number system.
- Real coefficients guide conforming polynomial factorization options.
- They ensure focus on solutions applicable to real-world, non-imaginary scenarios.
- Real coefficient polynomial representation simplifies calculations and analytical deductions.