Chapter 4: Problem 20
Factor the polynomial completely, and find all its zeros. State the multiplicity of each zero. \(Q(x)=x^{2}-8 x+17\)
Short Answer
Expert verified
Zeros: \(4+i, 4-i\), each with multiplicity 1.
Step by step solution
01
Recognize the Form
The polynomial given is a quadratic polynomial, specifically in the form \( ax^2 + bx + c \), where \( a = 1 \), \( b = -8 \), and \( c = 17 \). Since it is a quadratic, the first step in factoring is to determine if it can be factored using standard methods or a different approach is needed.
02
Check for Factorability Using the Discriminant
The discriminant \( \Delta \) of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( \Delta = b^2 - 4ac \). Substituting the values, we have \( \Delta = (-8)^2 - 4 \cdot 1 \cdot 17 = 64 - 68 = -4 \). Since the discriminant is negative, the polynomial does not have real roots and it can't be factored over the real numbers.
03
Find the Complex Roots
With a negative discriminant, the polynomial has complex roots, which can be found using the quadratic formula: \( x = \frac{-b \pm \sqrt{\Delta}}{2a} \). Substituting the values, we have: \[ x = \frac{-(-8) \pm \sqrt{-4}}{2 \cdot 1} = \frac{8 \pm i\sqrt{4}}{2} = \frac{8 \pm 2i}{2} = 4 \pm i \] The roots are \( 4+i \) and \( 4-i \).
04
Determine the Multiplicity
The roots \( 4+i \) and \( 4-i \) are each repeated once since they are the solutions to the quadratic equation. Therefore, both zeros \( 4+i \) and \( 4-i \) have a multiplicity of 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a fundamental tool in algebra for finding the roots of any quadratic equation of the form \( ax^2 + bx + c = 0 \). It is a formula that provides the solutions, or roots, for the equation by using the coefficients \( a \), \( b \), and \( c \). The quadratic formula is given as: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Using the formula involves three steps:
Using the formula involves three steps:
- Identify the coefficients \( a \), \( b \), and \( c \) from the quadratic equation.
- Calculate the discriminant \( \Delta = b^2 - 4ac \).
- Substitute these values into the formula to get the roots.
Complex Roots
Complex roots arise when the discriminant of a quadratic equation is negative. As was calculated in the original exercise, the discriminant \( \Delta = -4 \) is negative, which means the polynomial has complex rather than real solutions.
Complex numbers have two parts: a real part and an imaginary part. The imaginary part is derived from the square root of a negative number. In our case:
Complex numbers have two parts: a real part and an imaginary part. The imaginary part is derived from the square root of a negative number. In our case:
- The expression \( \sqrt{-4} \) turns into \( i\sqrt{4} \), where \( i \) is the imaginary unit, satisfying \( i^2 = -1 \).
- Real part: 4
- Imaginary part: \( \pm i \)
Discriminant in Quadratics
The discriminant in a quadratic equation is essential in determining the nature of the roots of the equation. For the quadratic \( ax^2 + bx + c = 0 \), the discriminant \( \Delta \) is calculated as \( b^2 - 4ac \). This value provides valuable insight:
- If \( \Delta > 0 \), the quadratic has two distinct real roots.
- If \( \Delta = 0 \), there is exactly one real root (a repeated root).
- If \( \Delta < 0 \), the roots are complex (as seen in this exercise).