Chapter 3: Problem 74
If \(f(x)=\sqrt{2 x-x^{2}}\) graph the following functions in the viewing rectangle \([-5,5]\) by \([-4,4] .\) How is each graph related to the graph in part (a)? $$ \begin{array}{ll}{\text { (a) } y=f(x)} & {\text { (b) } y=f(-x)} \\ {\text { (c) } y=-f(-x)} & {\text { (d) } y=f(-2 x)} \\ {\text { (e) } y=f\left(-\frac{1}{2} x\right)}\end{array} $$
Short Answer
Step by step solution
Understand the Parent Function
Simplify the Domain
Graph y=f(-x)
Graph y=-f(-x)
Graph y=f(-2x)
Graph y=f(-\frac{1}{2}x)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Domain
To find the domain, we solve the inequality \( 2x - x^2 \geq 0 \). By factoring, we get \( x(2 - x) \geq 0 \). This tells us that both \( x \) and \( 2 - x \) must be non-negative (greater than or equal to zero).
- If \( x \geq 0 \), then \( 2 - x \geq 0 \) implies \( x \leq 2 \).
- Combining these, we find \( 0 \leq x \leq 2 \).
Reflection
When we talk about \( y = f(-x) \), this represents a reflection over the y-axis. We essentially negate the x-values of the original function. For the function \( f(x) = \sqrt{2x - x^2} \), reflecting it over the y-axis would mean substituting \( x \) with \( -x \). However, since negative x-values within \([-2, 0]\) change back to positive \([0, 2]\) when squared and combined, the domain effectively remains the same as the original.
Similarly, \( y = -f(-x) \) involves a double reflection: first over the y-axis, resulting in \( f(-x) \), and then over the x-axis. This flips the graph upside down from the configuration achieved in \( f(-x) \). Through these processes, reflections help visualize symmetry in function graphs.
Horizontal Scaling
The transformation \( y = f(-2x) \) involves both a reflection and horizontal compression. The \(-2\) inside the function affects x directly, compressing the horizontal axis by a factor of two and reflecting it. To understand the domain of this transformation, solve \( 2(-2x) - (-2x)^2 \geq 0 \). Doing so gives us \(-1 \leq x \leq 0\).
For \( y = f\left(-\frac{1}{2}x\right) \), we are performing a horizontal stretch by a factor of two. By solving \( 2\left(-\frac{1}{2}x\right) - \left(-\frac{1}{2}x\right)^2 \geq 0 \), we determine the domain to be \(-4 \leq x \leq 0\). Here, the graph appears wider, reflecting a horizontal stretch.
Horizontal scaling changes how we perceive the spread of the graph but does not alter its general direction.
Quadratic Equation
The quadratic expression \( 2x - x^2 \) can be rewritten as \( x(2 - x) \), helping us solve for domain-related values. These factorized forms are crucial to determining where the graph of the function lies on the x-axis.
Quadratics like \( 2x - x^2 \) exhibit a characteristic parabolic shape, either opening upwards or downwards. Here, since it is expressed under a square root, the function only considers the top half of the parabola, where the expression is non-negative.
Understanding quadratics involves:
- Identifying its standard form \( ax^2 + bx + c \).
- Factoring to simplify and find roots or intervals.
- Utilizing graph transformations like reflection and scaling to understand how changes affect the parabola's graph.