Chapter 3: Problem 41
Find \(f(a), f(a+h),\) and the difference quotient \(\frac{f(a+h)-f(a)}{h},\) where \(h \neq 0\) $$ f(x)=3-5 x+4 x^{2} $$
Short Answer
Expert verified
\( f(a) = 3 - 5a + 4a^2 \), \( f(a+h) = 3 - 5a - 5h + 4a^2 + 8ah + 4h^2 \), difference quotient: \(-5 + 8a + 4h\).
Step by step solution
01
Evaluate f(a)
To find \( f(a) \), substitute \( a \) for \( x \) in the function \( f(x) = 3 - 5x + 4x^2 \). Thus, \( f(a) = 3 - 5a + 4a^2 \).
02
Evaluate f(a+h)
Substitute \( a+h \) for \( x \) in the function \( f(x) = 3 - 5x + 4x^2 \).\\( f(a+h) = 3 - 5(a+h) + 4(a+h)^2 \).\Now, expand \( (a+h)^2 \) to obtain \( a^2 + 2ah + h^2 \).\Thus, \( f(a+h) = 3 - 5a - 5h + 4(a^2 + 2ah + h^2) \).\This simplifies to \( f(a+h) = 3 - 5a - 5h + 4a^2 + 8ah + 4h^2 \).
03
Calculate the Difference Quotient
The difference quotient is given by \( \frac{f(a+h) - f(a)}{h} \). Substitute the expressions from Steps 1 and 2: \[\frac{(3 - 5a - 5h + 4a^2 + 8ah + 4h^2) - (3 - 5a + 4a^2)}{h}\]Simplify the numerator: the \( 3 \), \(-5a\), and \( 4a^2 \) terms cancel out, leaving:\[-5h + 8ah + 4h^2\].Factor \( h \) out of the numerator: \( h(-5 + 8a + 4h) \).Thus, the difference quotient simplifies to:\[-5 + 8a + 4h\].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Functions
Polynomial functions are expressions consisting of variables and coefficients, structured in a way where operations include addition, subtraction, multiplication, and non-negative integer exponents. They are fundamental in algebra and help describe various types of natural phenomena. In our given exercise, the function \(f(x) = 3 - 5x + 4x^2\) is a polynomial. Its degree is determined by the highest power of \(x\), which in this case is 2 (from \(4x^2\)), making it a quadratic polynomial.
- Linear Polynomial: Consists of terms up to the first degree. Example: \(ax + b\).
- Quadratic Polynomial: Involves terms up to the second degree. Example: \(ax^2 + bx + c\).
- Cubic Polynomial: Includes terms up to the third degree. Example: \(ax^3 + bx^2 + cx + d\).
Function Evaluation
Function evaluation involves finding the output of a function given specific inputs. This requires substituting values into a function's equation. In the context of our exercise, you evaluate \(f(a)\) by substituting \(a\) for \(x\) in the polynomial function \(f(x) = 3 - 5x + 4x^2\), yielding \(f(a) = 3 - 5a + 4a^2\). Similarly, for \(f(a+h)\), we replace \(x\) with \(a+h\), leading to more complex expressions due to the expanded terms.
- Evaluate with direct substitution: Often involves plugging in a given number or expression into each occurrence of the variable.
- Recognize the effect of change: Altering the variable by adding \(h\) results in additional terms that reveal how the function changes incrementally.
Algebraic Expressions
Algebraic expressions consist of a combination of numbers, variables, and arithmetic operations. Understanding how to manipulate these expressions is crucial in solving algebraic problems. In the context of our task, expressions like \(3 - 5x + 4x^2\) require careful handling, especially when expanded further through operations like squaring \((a+h)\).
Expansion and simplification are key processes:
Expansion and simplification are key processes:
- Expansion: Breaking down expressions into simpler parts, like how \((a+h)^2\) expands into \(a^2 + 2ah + h^2\).
- Simplification: Combining like terms and reducing expressions to their simplest forms. After expansion and substitution, it's crucial to combine terms where possible.