Chapter 3: Problem 20
Evaluate the function at the indicated values. $$ \begin{array}{l}{f(x)=x^{2}+2 x} \\ {f(0), f(3), f(-3), f(a), f(-x), f\left(\frac{1}{a}\right)}\end{array} $$
Short Answer
Expert verified
f(0) = 0, f(3) = 15, f(-3) = 3, f(a) = a^2 + 2a, f(-x) = x^2 - 2x, f(1/a) = 1/a^2 + 2/a.
Step by step solution
01
Evaluate f(0)
Substitute 0 into the function: \[ f(0) = 0^2 + 2 \times 0 = 0 \] Therefore, \( f(0) = 0 \).
02
Evaluate f(3)
Substitute 3 into the function: \[ f(3) = 3^2 + 2 \times 3 = 9 + 6 = 15 \] Therefore, \( f(3) = 15 \).
03
Evaluate f(-3)
Substitute -3 into the function: \[ f(-3) = (-3)^2 + 2 \times (-3) = 9 - 6 = 3 \] Therefore, \( f(-3) = 3 \).
04
Evaluate f(a)
Substitute \( a \) into the function: \[ f(a) = a^2 + 2a \] Therefore, \( f(a) = a^2 + 2a \).
05
Evaluate f(-x)
Substitute \( -x \) into the function: \[ f(-x) = (-x)^2 + 2(-x) = x^2 - 2x \] Therefore, \( f(-x) = x^2 - 2x \).
06
Evaluate \( f\left(\frac{1}{a}\right) \)
Substitute \( \frac{1}{a} \) into the function: \[ f\left(\frac{1}{a}\right) = \left(\frac{1}{a}\right)^2 + 2\left(\frac{1}{a}\right) = \frac{1}{a^2} + \frac{2}{a} \] Therefore, \( f\left(\frac{1}{a}\right) = \frac{1}{a^2} + \frac{2}{a} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Functions
Quadratic functions are a type of polynomial function. They are a fundamental concept in algebra. The standard form of a quadratic function is \( f(x) = ax^2 + bx + c \). Here, \( a \), \( b \), and \( c \) are constants, and \( a \) is not equal to zero. Quadratics form a curved shape on a graph, known as a parabola, which can open either upwards or downwards. This direction depends on the sign of \( a \).
In our problem, the function \( f(x) = x^2 + 2x \) is a quadratic function because it's expressed in the form of a second-degree polynomial, where \( a = 1 \), \( b = 2 \), and \( c = 0 \). Its graph is a parabola that opens upwards because the coefficient of \( x^2 \) is positive.
- If \( a > 0 \), the parabola opens upwards.
- If \( a < 0 \), the parabola opens downwards.
In our problem, the function \( f(x) = x^2 + 2x \) is a quadratic function because it's expressed in the form of a second-degree polynomial, where \( a = 1 \), \( b = 2 \), and \( c = 0 \). Its graph is a parabola that opens upwards because the coefficient of \( x^2 \) is positive.
Substitution
Substitution is a mathematical method used to replace variables with specific values. It’s commonly used in function evaluation to determine the output of a function for particular input values. Substitution is straightforward – you simply replace each instance of the variable in the function with the number you're evaluating.
For example, to evaluate \( f(x) = x^2 + 2x \) at \( x = 3 \), substitute \( 3 \) into the function:
Substitution is helpful for checking multiple values at once, as seen in the exercise where we evaluate \( f(x) \) at different inputs such as \( 0 \), \(-3\), and \( \frac{1}{a} \). Each substitution allows us to observe the function's behavior at various points.
For example, to evaluate \( f(x) = x^2 + 2x \) at \( x = 3 \), substitute \( 3 \) into the function:
- Original function: \( f(x) = x^2 + 2x \)
- Substitute \( x = 3 \): \( f(3) = 3^2 + 2 \times 3 \)
- Calculate: \( f(3) = 9 + 6 = 15 \)
Substitution is helpful for checking multiple values at once, as seen in the exercise where we evaluate \( f(x) \) at different inputs such as \( 0 \), \(-3\), and \( \frac{1}{a} \). Each substitution allows us to observe the function's behavior at various points.
Polynomial Functions
Polynomial functions consist of terms that include variables raised to whole-number powers. They can vary in complexity, from simple linear functions to complex, high-degree polynomials. In general, a polynomial function is expressed as \( f(x) = a_n x^n + a_{n-1} x^{n-1} + \dots + a_1 x + a_0 \), where \( n \) is the highest power of \( x \), also called the degree, and \( a_n \) are constants.
Quadratic functions, like \( f(x) = x^2 + 2x \), are a special type of polynomial function where the degree is 2. This makes them the simplest form of polynomial that isn't linear, which makes them a key focus in mathematics.
Quadratic functions, like \( f(x) = x^2 + 2x \), are a special type of polynomial function where the degree is 2. This makes them the simplest form of polynomial that isn't linear, which makes them a key focus in mathematics.
- The degree of a polynomial influences its graph's shape and the number of potential roots or solutions.
- In the context of solving and evaluating polynomials, understanding each term's role helps predict the function's overall behavior.