Chapter 2: Problem 40
(a) Sketch the line with slope \(-2\) that passes through the point \((4,-1)\) . (b) Find an equation for this line.
Short Answer
Expert verified
The line has equation \( y = -2x + 7 \).
Step by step solution
01
Understanding the Slope-Point Form of a Line
The slope-point form of a line is useful when we know a point on the line and the slope of the line. It is given by the formula \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is a point on the line.
02
Identify the Known Values
From the problem, we know the slope \( m = -2 \), and the point \((x_1, y_1)\) through which the line passes is \((4, -1)\).
03
Plug the Known Values into the Slope-Point Form
Substitute \( m = -2 \), \( x_1 = 4 \), and \( y_1 = -1 \) into the equation \( y - y_1 = m(x - x_1) \). This gives us \( y - (-1) = -2(x - 4) \).
04
Simplify the Equation
Simplify the expression to put it in the slope-intercept form \( y = mx + b \). Start by simplifying \( y + 1 = -2(x - 4) \). Distributing the \(-2\) gives \( y + 1 = -2x + 8 \). Then, solve for \( y \) to get \( y = -2x + 7 \).
05
Sketch the Line
To sketch the line, start at the point \((4, -1)\) on a coordinate plane. Use the slope, which is \(-2\), to determine the direction and steepness of the line: For every unit you move to the right along the x-axis, move 2 units down on the y-axis, since the slope is negative. Draw the line accordingly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Point Form
The slope-point form of an equation of a line is an essential tool for defining lines on a coordinate plane. This form is particularly helpful when you know one point on the line and the slope of the line. The formula for the slope-point form is:
When using this form, always substitute the known values directly into the equation. For instance, if you have a slope of \(-2\) and a point \((4, -1)\), substitute them into the formula to get:
- \( y - y_1 = m(x - x_1) \)
When using this form, always substitute the known values directly into the equation. For instance, if you have a slope of \(-2\) and a point \((4, -1)\), substitute them into the formula to get:
- \( y - (-1) = -2(x - 4) \)
Slope-Intercept Form
Once you have an equation in slope-point form, it's often useful to convert it into the slope-intercept form. This form is popular for its simplicity and clarity, showing both the slope and the y-intercept directly. The formula for slope-intercept form is:
To convert an equation from slope-point to slope-intercept form, expand and simplify the equation. Taking our example of \( y + 1 = -2(x - 4) \), distribute the slope to get:
- \( y = mx + b \)
To convert an equation from slope-point to slope-intercept form, expand and simplify the equation. Taking our example of \( y + 1 = -2(x - 4) \), distribute the slope to get:
- \( y + 1 = -2x + 8 \)
- \( y = -2x + 7 \)
Coordinate Plane
The coordinate plane is a fundamental concept in mathematics, serving as a space where we can graph equations and visualize relationships between variables. It is a two-dimensional surface divided by a horizontal line (x-axis) and a vertical line (y-axis), intersecting at a point called the origin \((0,0)\).
When sketching a line using the coordinates given by an equation, start by plotting specific points. For example, with a known point on the line \((4, -1)\), place this point on the coordinate plane to begin your drawing.
This is how you visualize equations like \( y = -2x + 7 \) on the coordinate plane, reflecting all the underlying relationships between the algebraic expressions and their geometric representations.
When sketching a line using the coordinates given by an equation, start by plotting specific points. For example, with a known point on the line \((4, -1)\), place this point on the coordinate plane to begin your drawing.
- The x-axis represents all possible values for \( x \).
- The y-axis shows all values for \( y \).
This is how you visualize equations like \( y = -2x + 7 \) on the coordinate plane, reflecting all the underlying relationships between the algebraic expressions and their geometric representations.