Chapter 2: Problem 11
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ y=-x $$
Short Answer
Expert verified
Both intercepts are at (0, 0). The graph is a line through the origin with slope -1.
Step by step solution
01
Understand the Equation
The given equation is \( y = -x \). This is a linear equation in slope-intercept form \( y = mx + b \), where the slope \( m = -1 \) and the y-intercept \( b = 0 \).
02
Create a Table of Values
Choose a few values for \( x \) and compute the corresponding \( y \) values using the equation \( y = -x \). For example: When \( x = -2 \), \( y = -(-2) = 2 \); when \( x = 0 \), \( y = 0 \); when \( x = 2 \), \( y = -2 \).
03
Plot the Points
Using the table of values from Step 2, plot the points on a coordinate plane. The points from the table include (-2, 2), (0, 0), and (2, -2).
04
Draw the Line
Connect the plotted points in a straight line extending through each point. This line represents the graph of the equation \( y = -x \).
05
Identify the Intercepts
For the y-intercept, set \( x = 0 \) in the equation to find \( y \): \( y = 0 \). This gives the y-intercept at the origin (0, 0). For the x-intercept, set \( y = 0 \) and solve for \( x \): \( 0 = -x \), which gives \( x = 0 \). Thus, the x-intercept is also at the origin (0, 0).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Linear Equations
Graphing linear equations involves plotting points on a coordinate plane and connecting them to form a line. It's a visual representation of relationships between variables. This can be understood through the equation provided, which is a linear function. In the example exercise, the equation given is \(y = -x\). This particular equation will create a line with a specific slope and intercept.
- First, you create a table of values. Select different values for \(x\) (such as -2, 0, and 2) and calculate the corresponding \(y\) values using the equation.
- For each \(x\), plug it into the equation to get \(y\). When \(x = -2\), \(y = 2\); when \(x = 0\), \(y = 0\); when \(x = 2\), \(y = -2\).
- These values form coordinate points (-2,2), (0,0), and (2,-2).
Slope-Intercept Form
The slope-intercept form is a way of expressing linear equations. It is represented as \(y = mx + b\) where \(m\) is the slope of the line and \(b\) is the y-intercept. Recognizing this form helps to quickly identify the slope and intercepts, crucial for graphing equations effectively. For the equation \(y = -x\), it is in slope-intercept form where the slope \(m\) is -1 and the y-intercept \(b\) is 0.
- The slope \(m = -1\) indicates that for every increase of 1 unit in \(x\), \(y\) decreases by 1 unit, suggesting a downward trend.
- The y-intercept \(b = 0\) implies that the line crosses the y-axis at the origin (0,0).
Intercepts
Intercepts are crucial points where the graph of an equation crosses the axes. Understanding intercepts helps in sketching graphs accurately. For linear equations, the x-intercept is where the line crosses the x-axis, and the y-intercept is where it crosses the y-axis.In the example of \(y = -x\), both the x-intercept and y-intercept occur at the origin (0,0).
- To find the y-intercept, set \(x = 0\) in the equation and solve for \(y\). Here, setting \(x = 0\) gives \(y = 0\), identifying the y-intercept at (0,0).
- For the x-intercept, set \(y = 0\) and solve for \(x\). Solving \(0 = -x\) gives \(x = 0\), indicating the x-intercept is also at (0,0).