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Making Words \(A\) toddler has wooden blocks showing the letters \(C, E, F, H, N,\) and \(R\) . Find the probability that the child arranges the letters in the indicated order. (a) In the order FRENCH (b) In alphabetical order

Short Answer

Expert verified
Both probabilities are \(\frac{1}{720}\).

Step by step solution

01

Understand the Total Arrangements

To solve the problem, we first need to calculate the total number of ways to arrange six letters. This can be done using the factorial function: there are 6 different letters and they can be arranged in \(6!\) different ways. Calculate \(6!\).
02

Calculate the Probability for Specific Arrangement (FRENCH)

The word 'FRENCH' is one specific arrangement among all possible arrangements. Hence, the probability of getting 'FRENCH' is \(\frac{1}{6!}\). Complete the division to find the probability.
03

Calculate the Probability for Alphabetical Order

For a group of letters arranged in alphabetical order, each letter must strictly follow its alphabetical successor. With unique letters, there is exactly one way to arrange them alphabetically. Thus, the probability is \(\frac{1}{6!}\).
04

Simplify Computations

Calculate the value of \(6! = 720\). Use this value to find both probabilities: \(\frac{1}{720}\) for both scenarios.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial Notation
Factorial notation is a mathematical concept used to denote the product of all positive integers up to a specified number. It is represented with an exclamation mark (e.g., 6!). In the context of counting, factorial notation helps determine how many ways you can arrange a set of different objects.
For example, if you have 6 letters like in our exercise, you compute 6! which equals 6 × 5 × 4 × 3 × 2 × 1. This translates to 720 different possible arrangements for those 6 letters.
Using factorials simplifies calculations in problems involving permutations, as it provides a systematic way to count arrangements without manually listing them all.
Permutations
Permutations refer to the arrangement of objects in a specific sequence or order. When dealing with permutations, the order of arrangement is crucial. With six distinct letters like our scenario, each different sequence of these letters represents a unique permutation.
To calculate permutations, we often use factorial notation, as it accounts for all possible sequences. When the order doesn't matter, combinations are considered, but in permutations, every arrangement is unique.
In our problem, each of the 720 arrangements of the letters C, E, F, H, N, and R is a different permutation. Specific permutations, like forming the word "FRENCH," can be seen as just one possible arrangement among the many.
Alphabetical Order
Alphabetical order involves arranging words or letters following the sequence of a standard order set by the alphabet. Each letter or set of letters follows or precedes another based on this order.
In the exercise, sorting the letters C, E, F, H, N, and R alphabetically means placing them from A to Z as it would appear in the dictionary. For unique letters, there is exactly one permutation where they fit perfectly into alphabetical order. That’s a key point in probability: only one out of all possible permutations will be the alphabetic set.
This is why arranging letters in alphabetical order results in a very specific arrangement, making the probability calculation relatively straightforward.
Probability Calculation
Probability is a measure of how likely an event is to occur. It is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
For example, determining the probability of the toddler arranging letters into the word 'FRENCH' involves identifying how many specific ways the word can be formed—just one—out of the 720 possible arrangements. This results in a probability of \( \frac{1}{720} \).
Similarly, the probability of the letters being arranged in alphabetical order is also \( \frac{1}{720} \), as there is only one specific sequence that fits this criterion. Such probability calculations play a critical role in understanding chance and randomness in different scenarios.

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Most popular questions from this chapter

A Game of Chance \(A\) box contains 100 envelopes. Ten envelopes contain \(\$ 10\) each, ten contain \(\$ 5\) each, two are "unlucky," and the rest are empty. A player draws an envelope from the box and keeps whatever is in it. If a person draws an unlucky envelope, however, he or she must pay \(\$ 100 .\) What is the expectation of a person playing this game?

Hitting a Target An archer normally hits the target with probability of \(0.6 .\) She hires a new coach for a series of special lessons. After the lessons she hits the target in five out of eight attempts. (a) Find the probability that she would have hit five or more out of the eight attempts before her lessons with the new coach. (b) Did the new coaching effective if the probability in part (a) is 0.05 or less.)

Selecting Cards Three cards are randomly selected from a standard 52 -card deck, one at a time, with each card replaced in the deck before the next one is picked. Find the probability of each event. (a) All three cards are hearts. (b) Exactly two of the cards are spades. (c) None of the cards is a diamond. (d) At least one of the cards is a club.

Complementary Combinations Without performing any calculations, explain in words why the number of ways of choosing two objects from ten objects is the same as the number of ways of choosing eight objects from ten objects. In general, explain why $$ C(n, r)=C(n, n-r) $$

Sweepstakes A sweepstakes offers a first prize of \(\$ 1,000,000,\) second prize of \(\$ 100,000,\) and third prize of \(\$ 10,000 .\) Suppose that two million people enter the contest and three names are drawn randomly for the three prizes. (a) Find the expected winnings for a person participating in this contest. (b) Is it worth paying a dollar to enter this sweepstakes?

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