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Evaluate the expression. $$ C(11,4) $$

Short Answer

Expert verified
C(11,4) is 330.

Step by step solution

01

Understand the Combinatorial Formula

The expression \( C(11,4) \) represents the number of ways to choose 4 items from a group of 11 without regard to the order of selection. This is a combination problem and can be calculated using the formula \( C(n, r) = \frac{n!}{r!(n-r)!} \).
02

Substitute Values into the Formula

Substitute \( n = 11 \) and \( r = 4 \) into the formula. This gives:\[C(11, 4) = \frac{11!}{4!(11-4)!} = \frac{11!}{4! \times 7!}\]
03

Simplify the Numerator

Calculate \( 11! \) but only up to the point where it can be simplified with \( 7! \) from the denominator. Since \( 11! = 11 \times 10 \times 9 \times 8 \times 7! \), it simplifies to a cancellation with \( 7! \):\[\frac{11 \times 10 \times 9 \times 8 \times 7!}{4! \times 7!} = \frac{11 \times 10 \times 9 \times 8}{4!}\]
04

Calculate the Denominator

Calculate \( 4! \):\[4! = 4 \times 3 \times 2 \times 1 = 24\]
05

Divide the Simplified Numerator by the Denominator

The problem is now reduced to dividing 11,880 by 24:\[\frac{11 \times 10 \times 9 \times 8}{24} = \frac{7920}{24} = 330\]
06

Verify the Calculation

Review the operations to ensure accuracy:1. Calculate \( 11 \times 10 \times 9 \times 8 = 7920 \)2. Divide 7920 by 24 to ensure accuracy: 7920 divided by 24 provides the expected result of 330.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

combinatorial formula
When dealing with problems of how to select objects from a larger set, we use a combination. The combinatorial formula comes in handy for this kind of calculation. This formula helps determine the number of ways to choose a subset of items from a larger pool, where the order of selection does not matter. The combinatorial formula can be expressed as:
  • The formula: \( C(n, r) = \frac{n!}{r!(n-r)!} \)
Here, \( n \) represents the total number of items available for selection, and \( r \) is the number of items to choose. This formula calculates the total possible combinations by considering permutations (all possible arrangements) and eliminating the redundancies by dividing with \( r! \). It also adjusts the total by the remaining items \((n-r)!\).
Using this formula always helps to break down complex counting problems into manageable calculations. It's essential in probability, statistics, and various fields needing selection without considering order, such as forming committees or teams.
factorial calculations
Factorials are a fundamental concept in combinatorial mathematics, represented by the symbol "!". Factorials are used to calculate the total number of ways to arrange a set of items. For a given number \( n \), the factorial \( n! \) is the product of all positive integers up to \( n \).
  • For example, \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
  • And generally, \( n! = n \times (n-1) \times (n-2) \times \ldots \times 1 \)
Factorials help simplify the combinatorial formula. In problems like finding \( C(11, 4) \), they allow us to handle the potentially large numbers generated during calculations. Understanding how to compute and manipulate factorials is crucial because you often need to cancel out terms when simplifying expressions, just like in the step-by-step original solution where \( 11! \) and \( 7! \) were involved. Neglecting this can lead to overwhelming calculations, so proper use of factorial calculations is crucial.
permutations and combinations
Permutations and combinations are two different ways of arranging or selecting items, considering or ignoring order, respectively. Both concepts are key in solving many probability and algebra problems.
  • Permutations: This involves arranging items where the order does matter. It's calculated by \( P(n, r) = \frac{n!}{(n-r)!} \) for \( n \) total things taken \( r \) at a time.
  • Combinations: Unlike permutations, combinations disregard order. This is where the combinatorial formula \( C(n, r) = \frac{n!}{r!(n-r)!} \) is applied.
Choosing the correct approach is crucial. For instance, when you need to select members for a team, combinations are your go-to since order doesn't impact the selection. However, if arranging books on a shelf, permutations are suitable because order changes outcomes.
Knowing the difference and application of both concepts ensures you approach each problem appropriately and avoid common mathematical errors.
binomial coefficient
A binomial coefficient is a specific application of combinations used within binomial expansions. Represented as \( \binom{n}{r} \), it indicates how many ways you can choose \( r \) items from \( n \) total, aligning directly with the combination expression \( C(n, r) \).
  • The binomial coefficient is expressed in the formula: \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
This coefficient acts as a scale factor in binomial theorem expansions, such as \((x + y)^n\). In such contexts, each term in the expansion corresponds to the binomial coefficient's role in dictating how many such ways variables can be combined.
Understanding the role of binomial coefficients also extends into fields such as probability, where they help compute the likelihood of a combination of outcomes occurring. Their depiction is both in numeric and symbolic forms and is fundamental to various combinatorial proofs and problems.

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