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Two vectors \(\mathbf{u}\) and \(\mathbf{v}\) are given. Find their dot product \(\mathbf{u} \cdot \mathbf{v} .\) $$ \mathbf{u}=\langle- 3,0,4\rangle, \quad \mathbf{v}=\left\langle 2,4, \frac{1}{2}\right\rangle $$

Short Answer

Expert verified
The dot product \( \mathbf{u} \cdot \mathbf{v} \) is \(-4\).

Step by step solution

01

Understand the Dot Product

The dot product of two vectors \( \mathbf{u} = \langle a_1, a_2, a_3 \rangle \) and \( \mathbf{v} = \langle b_1, b_2, b_3 \rangle \) is given by the formula \( \mathbf{u} \cdot \mathbf{v} = a_1b_1 + a_2b_2 + a_3b_3 \). We will apply this formula to find the dot product of \( \mathbf{u} \) and \( \mathbf{v} \).
02

Identify the Components

Identify the components of the vectors: \( \mathbf{u} = \langle -3, 0, 4 \rangle \) implies \( a_1 = -3 \), \( a_2 = 0 \), \( a_3 = 4 \) and \( \mathbf{v} = \langle 2, 4, \frac{1}{2} \rangle \) implies \( b_1 = 2 \), \( b_2 = 4 \), \( b_3 = \frac{1}{2} \).
03

Calculate Each Component Product

Compute the product of the corresponding components: \(-3 \times 2 = -6\), \(0 \times 4 = 0\), and \(4 \times \frac{1}{2} = 2\).
04

Sum the Component Products

Add the results of the component products to find the dot product: \(-6 + 0 + 2 = -4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vectors
Vectors are fundamental objects in mathematics, physics, and engineering that represent quantities having both magnitude and direction. Unlike scalars, which only have magnitude, vectors provide more comprehensive information about an object's movement or position.

Vectors are usually depicted as directed line segments, with an arrow indicating direction and length indicating magnitude. In the Cartesian coordinate system, vectors are expressed in terms of their components. For instance, vector \( \mathbf{u} = \langle -3, 0, 4 \rangle \) means it has components \(-3\), \(0\), and \(4\) aligned with the \(x\), \(y\), and \(z\) axes, respectively. This helps in describing the vector's position in 3-dimensional space.

When we deal with vectors notations like \( \langle a, b, c \rangle \), we are often interested in operations like addition, subtraction, and calculating dot products. These operations are vital for problem-solving across various fields.
Vector Components
Understanding vector components is crucial for performing calculations or depicting physical phenomena like forces and velocities. Each vector is often broken down into its components along the axes of the coordinate system it resides in, such as \(x\), \(y\), and \(z\) in 3-dimensional space.

Let's consider vector \(\mathbf{u} = \langle -3, 0, 4 \rangle\):
  • -3: This is the component along the x-axis. It tells us how far and in which direction the vector stretches horizontally.
  • 0: The y-component indicates no movement along the y-axis.
  • 4: The z-component shows the extent of movement along the vertical axis.

Knowing these components is pivotal when calculating the dot product or any vector operation, as they directly influence the result. Similarly, identifying the vector \( \mathbf{v} = \langle 2, 4, \frac{1}{2} \rangle \) provides an understanding of this vector’s behavior and interaction within 3D space.
Scalar Multiplication
Scalar multiplication is an operation where a vector is multiplied by a scalar (a single number). This alters the vector's magnitude without affecting its direction unless the scalar is negative, in which case the direction is reversed.

When computing a dot product, which involves scalar multiplication, it is essential to multiply each component of one vector by the corresponding component of another. For instance, the process transforms each vector into a product of scalars:\(-3 \times 2 = -6\), \(0 \times 4 = 0\), and \(4 \times \frac{1}{2} = 2\).

Finally, adding these scalar products, \(-6 + 0 + 2\), results in the dot product of \(-4\). This dot product represents a measure of similarity between the two vectors in terms of their direction and size. It has many applications, such as determining whether two vectors are perpendicular or finding the angle between them. Understanding scalar multiplication is key to mastering vector mathematics.

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Most popular questions from this chapter

Two direction angles of a vector are given. Find the third direction angle, given that it is either obtuse or acute as indicated. (In Exercises 43 and 44, round your answers to the nearest degree.) $$ \alpha=\frac{\pi}{3}, \quad \gamma=\frac{2 \pi}{3} ; \quad \beta \text { is acute } $$

(a) Calculate proj, \(\mathbf{u}\) . (b) Resolve \(\mathbf{u}\) into \(\mathbf{u}_{1}\) and \(\mathbf{u}_{2},\) where \(\mathbf{u}_{1}\) is parallel to \(\mathbf{v}\) and \(\mathbf{u}_{2}\) is orthogonal to \(\mathbf{v} .\) $$ \mathbf{u}=\langle 2,9\rangle, \quad \mathbf{v}=\langle- 3,4\rangle $$

Lines and Planes A line is parallel to the vector \(\mathbf{v},\) and a plane has normal vector \(\mathbf{n}\) . (a) If the line is perpendicular to the plane, what is the relationship between \(\mathbf{v}\) and \(\mathbf{n}\) (parallel or perpendicular)? (b) If the line is parallel to the plane (that is, the line and the plane do not intersect), what is the relationship between \(\mathbf{v}\) and \(\mathbf{n}(\text { parallel or perpendicular) } ?\) (c) Parametric equations for two lines are given. Which line is parallel to the plane \(x-y+4 z=6 ?\) Which line is perpendicular to this plane? Line \(1 : \quad x=2 t, \quad y=3-2 t, \quad z=4+8 t\) Line \(2 : \quad x=-2 t, \quad y=5+2 t, \quad z=3+t\)

Two vectors u and v are given. Find the angle (expressed in degrees) between u and v. $$ \mathbf{u}=\langle 4,0,2\rangle, \quad \mathbf{v}=\langle 2,-1,0\rangle $$

Find the direction angles of the given vector, rounded to the nearest degree. $$ \langle 2,3,-6\rangle $$

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