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Visualizing a Set in Space Try to visualize the set of all points \((X, y, z)\) in a coordinate space that are twice as far from the points \(Q(0,3,0)\) as from the point \(P(0,0,0) .\) Use the Distance Formula to show that the set is a sphere, and find its center and radius.

Short Answer

Expert verified
The sphere is centered at (0, -1, 0) with a radius of 2.

Step by step solution

01

Understanding the Condition

The set of points \( (x, y, z) \) is such that the distance to point \( Q(0,3,0) \) is twice the distance to point \( P(0,0,0) \). This can be mathematically expressed as: \\[\text{Distance}((x,y,z), Q) = 2 \times \text{Distance}((x,y,z), P)\]
02

Applying the Distance Formula

The distance of a point \( (x,y,z) \) from \( P(0,0,0) \) is given by \( \sqrt{x^2 + y^2 + z^2} \). The distance from \( (x,y,z) \) to \( Q(0,3,0) \) is \( \sqrt{x^2 + (y - 3)^2 + z^2} \).
03

Setting Up the Equation

Using the condition from Step 1, we have: \\[ \sqrt{x^2 + (y - 3)^2 + z^2} = 2 \sqrt{x^2 + y^2 + z^2} \] \Square both sides to eliminate the square roots.
04

Squaring Both Sides

After squaring both sides, the equation becomes: \\[ x^2 + (y - 3)^2 + z^2 = 4(x^2 + y^2 + z^2) \] \Simplify this equation.
05

Simplifying the Equation

Expand the left side to get: \( x^2 + y^2 - 6y + 9 + z^2 = 4(x^2 + y^2 + z^2) \). \Rearrange to solve for terms on one side: \( -3x^2 - 3y^2 - 3z^2 - 6y + 9 = 0 \).
06

Completing the Equation to Find the Sphere

Divide through by -3 to simplify: \( x^2 + y^2 + z^2 + 2y = 3 \). \Complete the square for \( y \): \( x^2 + (y+1)^2 + z^2 = 4 \).
07

Identifying the Sphere's Center and Radius

The equation \( x^2 + (y+1)^2 + z^2 = 4 \) represents a sphere. \The center of this sphere is \( (0,-1,0) \), and the radius is \( 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

sphere
The concept of a sphere is fundamental in 3D geometry. A sphere is a perfectly symmetrical three-dimensional shape, where all points on its surface are equidistant from a central point known as the "center". Imagine a basketball or a globe, these are examples of spherical objects. The defining characteristic of a sphere is that every point on its surface is at the same distance from its center.

Mathematically, if you want to describe a sphere in a coordinate space, you use the equation \[ (x - a)^2 + (y - b)^2 + (z - c)^2 = r^2\]where:
  • \((a, b, c)\) is the center of the sphere
  • \(r\) is the radius
  • \((x, y, z)\) represents any point on the sphere
By understanding this equation, you can easily visualize the sphere in a 3D space. In the exercise, solving the equation helps recognize the sphere's properties from given conditions.
center and radius
A sphere in coordinate space is defined by its center and radius. The center is a point \((a, b, c)\) and the radius is a constant distance \(r\) from this point to any point on the surface of the sphere.

To find the center and radius, it's essential to manipulate the algebraic representation of the sphere's equation into a recognizable form. Starting with a general quadratic expression like \[x^2 + (y - 3)^2 + z^2 = 4(x^2 + y^2 + z^2)\]you can simplify and rearrange terms, often by completing the square, to get it in a form like \[(x - a)^2 + (y - b)^2 + (z - c)^2 = r^2\], which directly gives you the center and the radius.

In the exercise provided, after completing the square, the equation for the sphere \[x^2 + (y+1)^2 + z^2 = 4\]is derived, leading to the conclusion that the center is \((0, -1, 0)\) with a radius of 2.
coordinate space
Coordinate space, specifically in three dimensions, is a framework for locating points using three coordinates: \(x\), \(y\), and \(z\). This system allows us to visualize geometric shapes and understand spatial relationships.

In 3D coordinate space, each point can be thought of as occupying a position along three mutually perpendicular axes. This is an extension from the 2D coordinate system, which only uses two axes (typically \(x\) and \(y\)). By adding the \(z\)-axis, we gain the ability to explore depth and height, enabling three-dimensional modeling of objects.

Understanding coordinate space is crucial when working with spheres, as it allows you to pinpoint the center and evaluate the distance from the center to any point, which is essentially the sphere's radius. The exercise uses these principles to determine the equation of a sphere by relating it visually in the space.

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