Chapter 1: Problem 63
Find all solutions of the equation, and express them in the form \(a+b i\) $$ x^{2}+x+1=0 $$
Short Answer
Expert verified
The solutions are \( x = -\frac{1}{2} + \frac{i\sqrt{3}}{2} \) and \( x = -\frac{1}{2} - \frac{i\sqrt{3}}{2} \).
Step by step solution
01
Recognize the Equation Form
The given equation is a quadratic equation of the form \( ax^2 + bx + c = 0 \). In this case, we have \( a=1, b=1, \) and \( c=1 \). This means we can apply the quadratic formula to find the solutions.
02
Apply the Quadratic Formula
The quadratic formula is given by \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute \( a = 1 \), \( b = 1 \), and \( c = 1 \) into the formula: \[ x = \frac{-1 \pm \sqrt{1^2 - 4 \times 1 \times 1}}{2 \times 1} \] This simplifies to: \[ x = \frac{-1 \pm \sqrt{1 - 4}}{2} \] \[ x = \frac{-1 \pm \sqrt{-3}}{2} \]
03
Simplify the Square Root of a Negative Number
The term \( \sqrt{-3} \) can be expressed as an imaginary number: \( \sqrt{-3} = i\sqrt{3} \). Substitute \( \sqrt{-3} = i\sqrt{3} \) into the expression: \[ x = \frac{-1 \pm i\sqrt{3}}{2} \]
04
Express in form \( a + bi \)
Now, simplify the results: \[ x = \frac{-1}{2} \pm \frac{i\sqrt{3}}{2} \] This gives us the two solutions as: \( x = -\frac{1}{2} + \frac{i\sqrt{3}}{2} \) and \( x = -\frac{1}{2} - \frac{i\sqrt{3}}{2} \). These solutions are already in the form \( a + bi \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Imaginary Numbers
Imaginary numbers might seem a bit puzzling at first, but they are easier to understand with a little practice. They are really just numbers that involve the square root of negative numbers. Usually, you cannot take the square root of a negative number within the realm of real numbers. That’s where imaginary numbers come into play.
When you see an expression like \( \sqrt{-3} \), it can be rewritten using the imaginary unit \( i \), where \( i = \sqrt{-1} \). So, \( \sqrt{-3} \) becomes \( i\sqrt{3} \).
When you see an expression like \( \sqrt{-3} \), it can be rewritten using the imaginary unit \( i \), where \( i = \sqrt{-1} \). So, \( \sqrt{-3} \) becomes \( i\sqrt{3} \).
- The concept of imaginary numbers extends our understanding of quantity and mathematical reality.
- They are a critical part of complex numbers, which combine both real and imaginary numbers.
Quadratic Formula
The quadratic formula is a reliable tool to solve any quadratic equation, no matter how complex. Standard quadratic equations have a form like \( ax^2 + bx + c = 0 \). The formula is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
This formula is very powerful because it gives solutions to any quadratic equation by converting the complex equation into a straightforward calculation.
This formula is very powerful because it gives solutions to any quadratic equation by converting the complex equation into a straightforward calculation.
- The expression under the square root \( b^2 - 4ac \) is called the discriminant.
- If the discriminant is positive, the equation has two distinct real solutions.
- If it is zero, there is one real solution.
- If it is negative, the solutions will be complex or imaginary.
Complex Numbers
Complex numbers are a crucial concept in mathematics, particularly useful for solving equations where imaginary numbers are involved. They take the form \( a + bi \), where \( a \) is the real part and \( bi \) represents the imaginary part. Complex numbers come in handy in various fields, including engineering and physics.
- Every real number can be considered a complex number with an imaginary part of zero.
- When you add or subtract complex numbers, you deal with the real and imaginary parts separately.
- Multiplication and division of complex numbers follow specific rules involving real and imaginary components.