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Simplify the rational expression. $$ \frac{y^{2}+y}{y^{2}-1} $$

Short Answer

Expert verified
The simplified expression is \(\frac{y}{y-1}\), with \(y \neq 1\) and \(y \neq -1\).

Step by step solution

01

Factor the Numerator

The expression in the numerator is a quadratic expression \(y^2 + y\). To factor it, identify a common factor in both terms. Here, we can factor out \(y\), resulting in \(y(y + 1)\).
02

Factor the Denominator

The expression in the denominator is \(y^2 - 1\), which is a difference of squares. The formula for the difference of squares is \(a^2 - b^2 = (a-b)(a+b)\). Here, \(a = y\) and \(b = 1\), so \(y^2 - 1 = (y-1)(y+1)\).
03

Simplify the Expression

Substitute the factored forms of the numerator and denominator back into the expression. We have: \(\frac{y(y+1)}{(y-1)(y+1)}\). Notice \(y+1\) appears in both the numerator and the denominator. This means we can cancel the common term \(y+1\). After cancellation, the simplified form is \(\frac{y}{y-1}\).
04

State Any Restrictions

When simplifying rational expressions, it's important to note the values that would make the denominator zero. In the original expression, \(y^2 - 1 = 0\) when \(y = 1\) or \(y = -1\). These values are restrictions since they make the original denominator zero. Hence, \(y eq 1\) and \(y eq -1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simplifying Rational Expressions
Simplifying rational expressions is an important skill in algebra. A rational expression is a fraction where both the numerator and the denominator are polynomials. To simplify it means making it as simple as possible, usually by reducing it to a form where no common factors are present in both numerator and denominator.

Let's start with a key step: **factoring**. This involves breaking down complex polynomial expressions into products of simpler polynomials. Factoring polynomials is crucial because it helps us identify parts of the expression that can be "cancelled" or reduced. Once we simplify using these methods, it becomes easier to work with these expressions in solving equations or evaluating limits.
Factoring Quadratics
Factoring quadratics involves breaking down expressions like y^2 + y into factors. These expressions are second-degree polynomials of the form y^2 + by + c .

In the exercise, the numerator y^2 + y is factored by finding common factors in its terms. We look for the greatest common factor, which in this case is y . So factoring gives us y(y + 1) .

Factoring quadratics can sometimes be trickier, especially when dealing with non-monic quadratics or those that do not immediately reveal a common factor. Learning the skill involves practice with different variations and learning to recognize patterns.
Difference of Squares
The difference of squares is a specific factoring technique used for expressions like y^2 - 1. It is based on the formula: \[a^2 - b^2 = (a-b)(a+b)\].

In the exercise, the denominator y^2 - 1 is a perfect example. Here, a is y, and b is 1, turning the expression into y^2 - 1 = (y-1)(y+1).

Recognizing a difference of squares can simplify your calculations significantly. It is important to identify these patterns because they often allow for cancellation and simplification in algebraic fractions and rational expressions.
Cancelling Common Factors
After factoring both the numerator and the denominator, the next step in simplifying a rational expression is to cancel out any common factors. Canceling is like reducing a numerical fraction by dividing out the same number. By effectively doing this, we simplify the expression.

For example, after factoring, the expression \(\frac{y(y+1)}{(y-1)(y+1)}\) allows us to cancel \((y+1)\) from both parts. After canceling, you're left with a simpler form: \(\frac{y}{y-1}\).

Always remember, when cancelling, first ensure that what you cancel is not 0. The values y = 1 and y = -1 are worth noting; these make the original denominator zero, and are thus restricted. Hence, it's important to state these restrictions clearly to keep the mathematical integrity of the expression intact.

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Most popular questions from this chapter

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