Chapter 8: Problem 84
Verify the identity. $$ \frac{\tan v-\cot v}{\tan ^{2} v-\cot ^{2} v}=\sin v \cos v $$
Short Answer
Expert verified
The identity is verified as both sides simplify to \( \sin v \cos v \).
Step by step solution
01
Rewrite tan and cot in terms of sine and cosine
Express \( \tan v \) and \( \cot v \) in terms of \( \sin v \) and \( \cos v \). Recall that \( \tan v = \frac{\sin v}{\cos v} \) and \( \cot v = \frac{\cos v}{\sin v} \).
02
Substitute values into the identity
Replace \( \tan v \) and \( \cot v \) in the equation \( \frac{\tan v - \cot v}{\tan^2 v - \cot^2 v} \) with \( \frac{\sin v}{\cos v} - \frac{\cos v}{\sin v} \) in the numerator and \( \left(\frac{\sin v}{\cos v}\right)^2 - \left(\frac{\cos v}{\sin v}\right)^2 \) in the denominator.
03
Simplify the numerator
Combine the terms in the numerator: \( \frac{\sin v}{\cos v} - \frac{\cos v}{\sin v} = \frac{\sin^2 v - \cos^2 v}{\sin v \cos v} \).
04
Simplify the denominator
Apply the difference of squares in the denominator: \( \left(\frac{\sin v}{\cos v}\right)^2 - \left(\frac{\cos v}{\sin v}\right)^2 = \frac{\sin^2 v}{\cos^2 v} - \frac{\cos^2 v}{\sin^2 v} = \frac{(\sin^4 v - \cos^4 v)}{\sin^2 v \cos^2 v} \).
05
Factor the difference of squares in denominator
Express \( \sin^4 v - \cos^4 v \) as a difference of squares: \((\sin^2 v)^2 - (\cos^2 v)^2 = (\sin^2 v - \cos^2 v)(\sin^2 v + \cos^2 v) \). The identity \( \sin^2 v + \cos^2 v = 1 \) simplifies this to \( \sin^2 v - \cos^2 v \).
06
Complete the simplification
Cancel \( \sin^2 v - \cos^2 v \) from the numerator and denominator: \( \frac{\sin^2 v - \cos^2 v}{\sin^2 v - \cos^2 v} \cdot \frac{\sin v \cos v}{\sin^2 v \cos^2 v} = \frac{\sin v \cos v}{\sin^2 v \cos^2 v} = \sin v \cos v \), confirming it equals the right side of the identity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of Squares
The concept of the difference of squares is a fundamental algebraic identity that simplifies expressions. When you see a difference like \( a^2 - b^2 \), it can be factored into \((a - b)(a + b)\). This principle helps to break down the expressions into simpler forms for easier manipulation. In the given problem, we see this applied in the step where \( \sin^4 v - \cos^4 v \) is rewritten. It becomes \( (\sin^2 v)^2 - (\cos^2 v)^2 \).
- Breaking it down: \((\sin^2 v - \cos^2 v)(\sin^2 v + \cos^2 v)\)
- Use the identity: \(\sin^2 v + \cos^2 v = 1\)
Simplifying Algebraic Expressions
Simplifying algebraic expressions involves reducing complex equations into simpler and more interpretable forms. In the context of the problem, simplifying involves a couple of steps, notably in the numerator and denominator of the fraction. First, rewriting \( \tan v \) and \( \cot v \) using sine and cosine to express the terms in a common framework is key. Then, combining and simplifying these terms:
- Numerator: \( \frac{\sin v}{\cos v} - \frac{\cos v}{\sin v} \) simplifies to \( \frac{\sin^2 v - \cos^2 v}{\sin v \cos v} \)
- Denominator: Transform difference of squares \((\frac{\sin^2 v}{\cos^2 v} - \frac{\cos^2 v}{\sin^2 v})\)
Trigonometric Functions
Trigonometric functions such as sine, cosine, tangent, and cotangent play a crucial role in forming these identities. Understanding their interrelations is fundamental. In our problem, knowing the identities \( \tan v = \frac{\sin v}{\cos v} \) and \( \cot v = \frac{\cos v}{\sin v} \) is vital, as we use them to express everything in terms of sine and cosine only. Trigonometric functions are interrelated:
- Basic identities like \( \sin^2 v + \cos^2 v = 1\) are key for simplification.
- The manipulation and rewriting of these into each other allows for simplification and verification of complex identities.