Chapter 8: Problem 68
59–76 Prove the identity. $$4\left(\sin ^{6} x+\cos ^{6} x\right)=4-3 \sin ^{2} 2 x$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 8: Problem 68
59–76 Prove the identity. $$4\left(\sin ^{6} x+\cos ^{6} x\right)=4-3 \sin ^{2} 2 x$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Verify the identity. $$ \sin ^{2} \alpha+\cos ^{2} \alpha+\tan ^{2} \alpha=\sec ^{2} \alpha $$
Verify the identity. $$ \sin ^{4} \theta-\cos ^{4} \theta=\sin ^{2} \theta-\cos ^{2} \theta $$
Verify the identity. $$ \frac{(\sin x+\cos x)^{2}}{\sin ^{2} x-\cos ^{2} x}=\frac{\sin ^{2} x-\cos ^{2} x}{(\sin x-\cos x)^{2}} $$
Verify the identity. $$ \cot ^{2} \theta \cos ^{2} \theta=\cot ^{2} \theta-\cos ^{2} \theta $$
Verify the identity. $$ \frac{\sin ^{3} x+\cos ^{3} x}{\sin x+\cos x}=1-\sin x \cos x $$
What do you think about this solution?
We value your feedback to improve our textbook solutions.